Difference between revisions of "2018 UNCO Math Contest II Problems/Problem 9"

(Created page with "== Problem == == Solution == == See also == {{UNCO Math Contest box|year=2018|n=II|num-b=8|num-a=10}} [[Category:]]")
 
(Problem)
Line 1: Line 1:
 
== Problem ==
 
== Problem ==
 
+
Call a set of integers Grassilian if each of its elements is at least as large as the number of
 
+
elements in the set. For example, the three-element set <math>\{2, 48, 100\}</math> is not Grassilian, but the
 +
six-element set <math>\{6, 10, 11, 20, 33, 39\}</math> is Grassilian. Let <math>G(n)</math> be the number of Grassilian subsets of <math>\{1, 2, 3, ..., n\}</math>. (By definition, the empty set is a subset of every set and is Grassilian.)
 +
(a) Find <math>G(3)</math>, <math>G(4)</math>, and <math>G(5)</math>.
 +
(b) Find a recursion formula for <math>G(n + 1)</math>. That is, find a formula that expresses <math>G(n + 1)</math> in
 +
terms of <math>G(n), G(n  1),\;dots</math>
 +
(c) Give an explanation that shows that the formula you give is correct.
  
 
== Solution ==
 
== Solution ==

Revision as of 01:31, 14 January 2019

Problem

Call a set of integers Grassilian if each of its elements is at least as large as the number of elements in the set. For example, the three-element set $\{2, 48, 100\}$ is not Grassilian, but the six-element set $\{6, 10, 11, 20, 33, 39\}$ is Grassilian. Let $G(n)$ be the number of Grassilian subsets of $\{1, 2, 3, ..., n\}$. (By definition, the empty set is a subset of every set and is Grassilian.) (a) Find $G(3)$, $G(4)$, and $G(5)$. (b) Find a recursion formula for $G(n + 1)$. That is, find a formula that expresses $G(n + 1)$ in terms of $G(n), G(n  1),\;dots$ (c) Give an explanation that shows that the formula you give is correct.

Solution

See also

2018 UNCO Math Contest II (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10
All UNCO Math Contest Problems and Solutions

[[Category:]]