2020 AMC 8 Problems/Problem 15

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Problem 15

Suppose $15\%$ of $x$ equals $20\%$ of $y.$ What percentage of $x$ is $y?$

$\textbf{(A) }5 \qquad \textbf{(B) }35 \qquad \textbf{(C) }75 \qquad \textbf{(D) }133 \frac13 \qquad \textbf{(E) }300$

Solution 1

We set up the following equation based on the given information: \[\frac{15x}{100}=\frac{20y}{100}\] Solving for $x$ yields \[\frac{3x}{20}=\frac{y}{5}\] \[20y=15x\] \[x=1.\overline{3}y ==> D\]

See also

2020 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Problem 16
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All AJHSME/AMC 8 Problems and Solutions

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