Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "2020 AMC 8 Problems/Problem 2"
Line 5: Line 5:
  
 
==Solution==
 
==Solution==
−
First we average <math>15,20,25,40</math> to get <math>25</math>. Thus, <math>40 - 25 = \boxed{\textbf{(C) }\$15.}</math>. ~~Spaced_Out
+
First we average <math>15,20,25,40</math> to get <math>25</math>. Thus, <math>40 - 25 = \boxed{\textbf{(C) }\$15.}</math>. ~~Spaced_Out Note if you get <math>100 once adding it up and then /4= </math>15 or \boxed{\textbf{(C) }.
−
 
+
<math>oceanxia
 
==Solution 2==
 
==Solution 2==
−
The total earnings for the four friends is <math>\$15+\$20+\$25+\$40=\$100</math>. Since they decided to split their earnings equally among themselves, it follows that each person will get <math>\frac{\$100}{4}=\$25</math>. Since the friend who earned <math>\$40</math> will need to leave with <math>\$25</math>, he will have to give <math>\$40-\$25=\$15</math> to the others <math>\implies\boxed{\textbf{(C) }\$15}</math>.<br>
+
The total earnings for the four friends is </math>\$15+\$20+\$25+\$40=\$100<math>. Since they decided to split their earnings equally among themselves, it follows that each person will get </math>\frac{\$100}{4}=\$25<math>. Since the friend who earned </math>\$40<math> will need to leave with </math>\$25<math>, he will have to give </math>\$40-\$25=\$15<math> to the others </math>\implies\boxed{\textbf{(C) }\$15}$.<br>
 
~[http://artofproblemsolving.com/community/user/jmansuri junaidmansuri]
 
~[http://artofproblemsolving.com/community/user/jmansuri junaidmansuri]
  

Revision as of 18:56, 19 November 2020

Problem 2

Four friends do yardwork for their neighbors over the weekend, earning $$15, $20, $25,$ and $$40,$ respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned $$40$ give to the others?

$\textbf{(A) }$5 \qquad \textbf{(B) }$10 \qquad \textbf{(C) }$15 \qquad \textbf{(D) }$20 \qquad \textbf{(E) }$25$

Solution

First we average $15,20,25,40$ to get $25$. Thus, $40 - 25 = \boxed{\textbf{(C) }$15.}$. ~~Spaced_Out Note if you get $100 once adding it up and then /4=$15 or \boxed{\textbf{(C) }. $oceanxia ==Solution 2== The total earnings for the four friends is$$15+$20+$25+$40=$100$. Since they decided to split their earnings equally among themselves, it follows that each person will get$\frac{$100}{4}=$25$. Since the friend who earned$$40$will need to leave with$$25$, he will have to give$$40-$25=$15$to the others$\implies\boxed{\textbf{(C) }$15}$.
~junaidmansuri

Video Solution

https://youtu.be/-mSgttsOv2Y

~savannahsolver

See also

2020 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 1 		Followed by
Problem 3
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2020_AMC_8_Problems/Problem_2&oldid=137879"