# Difference between revisions of "2020 AMC 8 Problems/Problem 2"

## Problem 2

Four friends do yardwork for their neighbors over the weekend, earning $15, 20, 25,$ and $40,$ respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned $40$ give to the others?

$\textbf{(A) }5 \qquad \textbf{(B) }10 \qquad \textbf{(C) }15 \qquad \textbf{(D) }20 \qquad \textbf{(E) }25$

## Solution

First we average $15,20,25,40$ to get $25$. Thus, $40 - 25 = \boxed{\textbf{(C) }15.}$. ~~Spaced_Out Note if you get $100 once adding it up and then /4=$15 or \boxed{\textbf{(C) }. $oceanxia ==Solution 2== The total earnings for the four friends is$$15+$20+$25+$40=$100$. Since they decided to split their earnings equally among themselves, it follows that each person will get$\frac{$100}{4}=$25$. Since the friend who earned$$40$will need to leave with$$25$, he will have to give$$40-$25=$15$to the others$\implies\boxed{\textbf{(C) }$15}$.
~junaidmansuri

~savannahsolver