Difference between revisions of "2020 AMC 8 Problems/Problem 3"
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==Solution 2== | ==Solution 2== | ||
Looking at the units of each quantity, we observe that the answer will be the product of the number of square feet, the number of plants per square foot, and the number of strawberries per plant. This gives <math>6 \cdot 8 \cdot 4 \cdot 10 = \boxed{\textbf{(D) }1920}</math>. | Looking at the units of each quantity, we observe that the answer will be the product of the number of square feet, the number of plants per square foot, and the number of strawberries per plant. This gives <math>6 \cdot 8 \cdot 4 \cdot 10 = \boxed{\textbf{(D) }1920}</math>. | ||
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+ | ==Solution 3 (One-Line Version of Solution 2)== | ||
+ | <cmath>\left(6\text{ ft}\cdot8\text{ ft}\right)\left(4 \ \frac{\text{plants}}{\text{ft}^2}\right)\left(10 \ \frac{\text{strawberries}}{\text{plant}}\right)=6\cdot8\cdot4\cdot10=\boxed{\textbf{(D) }1920} \text{ strawberries}</cmath> | ||
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+ | ~MRENTHUSIASM | ||
==Video Solution by WhyMath== | ==Video Solution by WhyMath== |
Revision as of 00:28, 5 March 2021
Contents
Problem
Carrie has a rectangular garden that measures feet by feet. She plants the entire garden with strawberry plants. Carrie is able to plant strawberry plants per square foot, and she harvests an average of strawberries per plant. How many strawberries can she expect to harvest?
Solution 1
The area of the garden is square feet. Since Carrie plants strawberry plants per square foot, there are a total of strawberry plants, each of which produces strawberries on average. Accordingly, she can expect to harvest strawberries.
Solution 2
Looking at the units of each quantity, we observe that the answer will be the product of the number of square feet, the number of plants per square foot, and the number of strawberries per plant. This gives .
Solution 3 (One-Line Version of Solution 2)
~MRENTHUSIASM
Video Solution by WhyMath
~savannahsolver
Video Solution
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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