Difference between revisions of "2023 AMC 8 Problems/Problem 1"

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==Solution 1 ==  
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==Problem 1==
  
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What is the value of <math>(8 \times 4 + 2) - (8 + 4 \times 2)</math>?
  
<math>(8\times4 + 2)-(8+4\times2)= (32+2) - (8+8) = 34 - 16 = \boxed{\text{(D)}\hspace{0.1 in} 18}</math>
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<math>\textbf{(A)}\ 0 \qquad \textbf{(B)}\ 6 \qquad \textbf{(C)}\ 10 \qquad \textbf{(D)}\ 18 \qquad \textbf{(E)}\ 24</math>
 
 
 
 
~apex304, TaeKim
 
  
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==Solution 1 ==
  
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By the order of operations, we have
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<cmath>(8 \times 4 + 2) - (8 + 4 \times 2) = (32+2) - (8+8) = 34 - 16 = \boxed{\textbf{(D)}\ 18}.</cmath>
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~apex304, TaeKim, peelybonehead, MRENTHUSIASM
  
==Solution 2==
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==See Also==
Follow PEMDAS to get <math>\boxed{\text{(D)}\hspace{0.1 in} 18}.</math>
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{{AMC8 box|year=2023|before=First Problem|num-a=2}}
~peelybonehead
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{{MAA Notice}}

Revision as of 23:51, 24 January 2023

Problem 1

What is the value of $(8 \times 4 + 2) - (8 + 4 \times 2)$?

$\textbf{(A)}\ 0 \qquad \textbf{(B)}\ 6 \qquad \textbf{(C)}\ 10 \qquad \textbf{(D)}\ 18 \qquad \textbf{(E)}\ 24$

Solution 1

By the order of operations, we have \[(8 \times 4 + 2) - (8 + 4 \times 2) = (32+2) - (8+8) = 34 - 16 = \boxed{\textbf{(D)}\ 18}.\] ~apex304, TaeKim, peelybonehead, MRENTHUSIASM

See Also

2023 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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