Difference between revisions of "2023 AMC 8 Problems/Problem 17"

(Undo revision 187794 by Mayowl (talk) whyd u delete that)
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==Solution (Intuition)==
 
==Solution (Intuition)==
 
The answer is <math>\boxed{\textbf{(A)}\ 1}.</math> Use intuition to bring it down to <math>2</math> guesses <math>1</math> or <math>2</math> and guess from there or you could actually fold the paper.
 
The answer is <math>\boxed{\textbf{(A)}\ 1}.</math> Use intuition to bring it down to <math>2</math> guesses <math>1</math> or <math>2</math> and guess from there or you could actually fold the paper.
 
+
-apex304
 
==Animated Video Solution==
 
==Animated Video Solution==
 
https://youtu.be/ECqljkDeA5o
 
https://youtu.be/ECqljkDeA5o

Revision as of 09:55, 25 January 2023

Problem

A regular octahedron has eight equilateral triangle faces with four faces meeting at each vertex. Jun will make the regular octahedrons shown on the right by folding the piece of paper shown on the left. Which numbered face will end up to the right of $Q$?

2023 AMC 8-17.png

Solution (Intuition)

The answer is $\boxed{\textbf{(A)}\ 1}.$ Use intuition to bring it down to $2$ guesses $1$ or $2$ and guess from there or you could actually fold the paper. -apex304

Animated Video Solution

https://youtu.be/ECqljkDeA5o

~Star League (https://starleague.us)

Video Solution by OmegaLearn (Using 3D Visualization)

https://youtu.be/gIjhiw1CUgY

See Also

2023 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 16
Followed by
Problem 18
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png