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  • path h = ellipse((0.5,0),0.45,0.015), v = ellipse((0,0.5),0.015,0.45); filldraw(shift((j,i))*v,black);
    4 KB (609 words) - 19:49, 27 August 2023
  • Now all these nine polyhedrons lie inside <math>2 P_1</math>. Let <math>V</math> be the volume of <math>P_1</math>.
    1 KB (242 words) - 13:55, 29 January 2021
  • The volume <math>V = \pi R^2H</math> is to be increased by the same fixed positive amount when
    1 KB (245 words) - 19:07, 17 May 2018
  • https://www.youtube.com/watch?v=sT-wxV2rYqs ...AC = b, AB = c, x_1 = BX, x_2 = CX, \frac{c+t}{x_1} = u, \frac{b+t}{x_2} = v.</math>
    13 KB (2,200 words) - 21:36, 6 January 2024
  • ..., we can always choose <math>3-r</math> as the remainder for our set <math>V</math>, giving us a total of <math>r + 3 - r \equiv 0 \pmod{3}</math>. The
    26 KB (4,044 words) - 13:58, 24 January 2024
  • <cmath>v_{13}(27^m-1^m)=v_{13}(26)+v(m)=1+v(m), 3m = n</cmath> which clearly implies <math>m=13</math> and <math>39 | n
    10 KB (1,448 words) - 06:30, 21 April 2024
  • ...<math>1800-x</math>. Since Eve is the slowest, we can call her speed <math>v</math>, so that Ina's speed is <math>2v</math> and Paul's speed is <math>4v ...e of <math>1800-x</math> which takes them a time of <math>\frac{1800-x}{4v+v}</math>. Paul must run the same distance back to <math>B</math>, so his tot
    3 KB (516 words) - 03:25, 16 January 2023
  • ...ots, v_n), \vec{w} = (w_1, \cdots, w_n)</math> is defined to be <math>\vec{v}\cdot\vec{w} = \sum_{i=1}^n v_i w_i</math>. The dot product is [[linear|bil ...el, from which the identity <math>\vec{v} \cdot \vec{v} = \left \Vert \vec{v} \right \Vert ^2</math> follows.
    1 KB (199 words) - 23:10, 19 February 2022
  • ...B travels half the time at <math>u</math> miles per hour and half at <math>v</math> miles per hour. The average speed of Car A is <math>x</math> miles p <cmath>y = \frac{u+v}{2}</cmath>
    2 KB (396 words) - 19:03, 22 June 2021
  • Let the volume of the trough be <math>V</math> liters. Also, let the rate of the cold water tap be <math>C</math> <cmath>V = 21E</cmath>
    1 KB (268 words) - 16:32, 28 July 2018
  • Of the following five statements, I to V, about the binary operation of averaging (arithmetic mean), <math>\text{V. Averaging has an identity element }</math>
    2 KB (432 words) - 13:57, 20 February 2020
  • ...positions of the midpoints <math> U</math> of <math> BA</math> and <math> V</math> of <math> AC</math> as <math> \angle OPA</math> varies?
    3 KB (499 words) - 13:29, 2 August 2021
  • <math>\quad\bullet\qquad</math> <math>V,</math> a reflection across the <math>y</math>-axis. ...beled vertices back to their original positions? (For example, <math>R, R, V, H</math> is one sequence of <math>4</math> transformations that will send
    16 KB (2,496 words) - 20:09, 19 May 2024
  • ...P}\setminus\{\mathbf{v}\}</math> obtained by omitting vector <math>\mathbf{v}</math> from <math>\mathcal{P}</math> can be partitioned into two sets of e
    2 KB (369 words) - 23:35, 21 April 2019
  • ...P}\setminus\{\mathbf{v}\}</math> obtained by omitting vector <math>\mathbf{v}</math> from <math>\mathcal{P}</math> can be partitioned into two sets of e
    531 bytes (88 words) - 23:37, 21 April 2019
  • ...egree of <math>V</math> (i.e. the number of edges coming into/out of <math>V</math>). This is because to visit any of these vertices, we would have to e ...isit each vertex <math>M(V)</math> times, and must traverse <math>2\cdot M(V)</math> edges connected to each vertex. Specifically, we must traverse all
    8 KB (1,306 words) - 22:18, 1 February 2020
  • 'v'
    19 KB (2,942 words) - 21:22, 21 January 2024
  • Let <math>P(3)=u</math> and <math>P(4) = v</math>. Substituting <math>x=3</math> and <math>x=4</math> into the above q u &= (3-u)(3-v) = 9 - 3u - 3v + uv\\
    10 KB (1,819 words) - 19:34, 17 September 2023
  • ...ngineer Panagiotis Verdes figured out how to make 6×6 and 7×7 cubes. The V-Cube 6 (a 6x6x6 Rubik’s cube) has 157 152 858 401 024 063 281 013 959 519 The 7x7x7 Rubik’s cube (the V-Cube 7) has 19 500 551 183 731 307 835 329 126 754 019 748 794 904 992 692
    5 KB (518 words) - 16:53, 19 February 2024
  • <math>\delta x'(t)=v(t)</math> <math>v'(t)=a(t)</math>
    3 KB (423 words) - 12:58, 8 July 2019
  • ...he base's area, and h is the height's length; for a pyramid, we have <math>V=\frac{1}{3}Bh</math>.
    1 KB (207 words) - 01:39, 15 January 2020
  • 231. Almighty Gmaas once demanded Epic Games to give him 5,000,000 V-bucks for his 569823rd birthday. EDIT: This is why Almighty Gmaas no longer
    85 KB (13,971 words) - 18:02, 16 May 2024
  • label("V", (2, 6), NE); label("V", (2, 6), NE);
    11 KB (1,770 words) - 08:56, 17 May 2024
  • <math>\quad\bullet\qquad</math> <math>V,</math> a reflection across the <math>y</math>-axis. ...beled vertices back to their original positions? (For example, <math>R, R, V, H</math> is one sequence of <math>4</math> transformations that will send
    10 KB (1,653 words) - 23:33, 3 August 2023
  • ...of a cone is <math>\frac{1}{3}\pi r^{2}h</math>. Plugging in we find <math>V = 3\pi \sqrt{7} \implies \boxed{\textbf{(C)}}</math>
    3 KB (493 words) - 16:14, 11 September 2023
  • ...the origin and select a point on each line to define vectors <math>\mathbf{v}_{i}=(x_{i},y_{i})</math>. <cmath>\mathbf{v}_1\cdot\mathbf{v}_2 = v_{1}v_{2}\cos\theta \quad\mathrm{and}\quad
    5 KB (895 words) - 15:03, 8 June 2023
  • <li><math>\log_b{(uv)}=\log_b u + \log_b v.</math></li><p>
    5 KB (680 words) - 16:40, 22 April 2024
  • Let <math>V</math> and <math>F</math> be the vertex and focus of the Parabola <math>P(x
    8 KB (1,223 words) - 15:02, 27 November 2022
  • ...an upright V.}\\ \textbf{(D)}\ \text{Two line segments forming an inverted V.}\\ \textbf{(E)}\ \text{None of these.}</math>
    1 KB (193 words) - 10:42, 6 July 2020
  • ...d a horizontal circle of radius <math>r</math> with a constant speed <math>v</math>, in a conical pendulum. The center of the circle is vertically below ...ath>16 kg</math> which slides at a speed of <math>v</math>, with <math>u > v</math>. Block A slides east while Block B slides in west. The surface has c
    2 KB (439 words) - 11:52, 1 August 2020
  • ...th>x=PT</math>, where the length <math>O_{1}O_{2}</math> splits as <math>u+v</math>. Because the lines <math>PQ</math> and <math>O_{1}O_{2}</math> are p ...u^{2}+(r+x)^{2}-u(r+x) \\ \triangle O_{1}OT&:(r+R_{1})^{2}=v^{2}+(r+x)^{2}+v(r+x)\end{align*}</cmath>
    17 KB (2,852 words) - 03:59, 7 February 2024
  • Lucky Seven V ARE YOU XPERIENCED? V
    3 KB (452 words) - 10:21, 17 November 2022
  • Suppose that on a parabola with vertex <math>V</math> and a focus <math>F</math> there exists a point <math>A</math> such
    15 KB (2,383 words) - 09:49, 25 June 2023
  • Denote <math>u = 1 - x</math>, <math>v = 1 - y</math>, <math>w = 1 - z</math>. \sqrt{(1-u)(1+v)} + \sqrt{(1+u)(1-v)} & = 1 \hspace{1cm} (1) \\
    15 KB (2,208 words) - 01:25, 1 February 2024
  • ...t{10}} , \sqrt{10} \right)</math>, <math>Q = \left( \sqrt{10} , \frac{10 - v}{\sqrt{10}} \right)</math>. We have <math>m_{HP} = \frac{3}{6 - u}</math> and <math>m_{PQ} = - \frac{v}{u}</math>.
    16 KB (2,274 words) - 09:02, 10 December 2022
  • Let <math>O</math> be the center of the base, <math>V</math> be the vertex of the base.
    8 KB (1,314 words) - 03:54, 5 July 2022
  • pair A, B, C, D, E, F, G, H, A1, B1, C1, D1, E1, F1, G1, H1, V; V = (3,0);
    24 KB (3,567 words) - 18:14, 30 August 2022
  • Now here comes the smart part. Substitute <math>y = \sqrt[3]{u} - \sqrt[3]{v}</math>. ...<math>u - 3\sqrt[3]{u^2v} + 3\sqrt[3]{uv^2} - v + p\sqrt[3]{u} - p\sqrt[3]{v} + q = 0</math>. Simplification:
    6 KB (1,059 words) - 14:42, 11 December 2020
  • Let <math>u = 10 – y, v = 9 – x.</math> https://www.youtube.com/watch?v=jDP2PErthkg
    5 KB (794 words) - 15:36, 30 August 2022
  • ...3}</math> then we can find a line <math>\ell</math> perpendicular to <math>v</math> such that <math>\ell</math> separates <math>S</math>, and any point Suppose there is no such direction <math>v</math>, then <math>S</math> is contained in a box with side length <math>n^
    3 KB (574 words) - 11:30, 14 May 2021
  • Suppose that on a parabola with vertex <math>V</math> and a focus <math>F</math> there exists a point <math>A</math> such ...d <math>Y</math> be the orthogonal projections of <math>F</math> and <math>V</math> onto <math>AQ</math>. Because <math>AF < AV</math>, there are two po
    4 KB (796 words) - 17:33, 13 July 2021
  • ...ur squares on the middle of the edges after n moves, and <math>V_n</math> (V for vertex) be the probability that Frieda is on a corner after n moves. Th https://youtube.com/watch?v=kHLR57iP0cU
    17 KB (2,801 words) - 07:29, 4 November 2022
  • ...<math>u</math> and <math>v</math> in <math>G</math>. Every tree on <math>|V|=n</math> vertices has exactly <math>n-1</math> edges.
    401 bytes (75 words) - 16:51, 2 November 2020
  • V&=\frac16\cdot AB\cdot AD\cdot BD \\
    3 KB (496 words) - 19:12, 28 October 2022
  • ...tuy + vy^2 + svy + tv</math>, simplifying to <math>y^4 + (s + u)y^3 + (t + v + su)y^2 + (sv + tu)y + tv</math>. [[Equating coefficients]] gives the foll ...begin{cases} s + u = 0 \text{ since the } y^3 \text{ term is 0} \\ p = t + v + su \\ q = sv + tu \\ r = tv \end{cases}</math>
    13 KB (2,376 words) - 16:56, 19 February 2024
  • ...</math> and <math>2</math> along <math>\textbf{u}</math> and <math>\textbf{v}</math> respectively, then find <cmath>\sum_{i=1}^{n}\|\textbf{r}_i\|^2.</c
    7 KB (1,149 words) - 17:16, 15 December 2020
  • ...đến sâu răng, mất răng. Vì vậy, cần phát hiện kịp thời và điều trị đúng cách mòn cổ răng. ...rãnh này, lâu dần tạo mảng bám, gây viêm nhiễm, tụt lợi và ảnh hưởng tới thẩm mỹ. Cổ răng mòn nhiều thậm chí có
    5 KB (1,261 words) - 05:15, 7 January 2021
  • ...math> OV</math> (but not in <math> \vec{OV}</math>) for some vertex <math> V</math> of the polygon. Each two of these lines are obtained one from anothe
    2 KB (284 words) - 11:02, 30 January 2021
  • label("V",(1.5,.3),N); ...>\text{(A)}\ \text{Z} \qquad \text{(B)}\ \text{U} \qquad \text{(C)}\ \text{V} \qquad \text{(D)}\ \ \text{W} \qquad \text{(E)}\ \text{Y}</math>
    1,023 bytes (167 words) - 15:57, 4 July 2023
  • If <math>V = gt + V_0</math> and <math>S = \frac {1}{2}gt^2 + V_0t</math>, then <math> <math> \textbf{(A)}\ \frac{2S}{V+V_0}\qquad
    737 bytes (129 words) - 22:53, 12 February 2021

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