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Talk:Geometric inequality

Revision as of 00:10, 29 April 2008 by Clee (talk | contribs)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Shouldn't the sign for the Isoperimetric Inequality be $\le$ not $<$ since a circle is a figure and $\frac{4 \pi (\pi r^{2})}{(2 \pi r)^{2}}=1$?

--Xantos C. Guin 19:26, 24 June 2006 (EDT)

That's what I think, too. Fixed.

--CLee

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