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k a May Highlights and 2025 AoPS Online Class Information
jlacosta   0
May 1, 2025
May is an exciting month! National MATHCOUNTS is the second week of May in Washington D.C. and our Founder, Richard Rusczyk will be presenting a seminar, Preparing Strong Math Students for College and Careers, on May 11th.

Are you interested in working towards MATHCOUNTS and don’t know where to start? We have you covered! If you have taken Prealgebra, then you are ready for MATHCOUNTS/AMC 8 Basics. Already aiming for State or National MATHCOUNTS and harder AMC 8 problems? Then our MATHCOUNTS/AMC 8 Advanced course is for you.

Summer camps are starting next month at the Virtual Campus in math and language arts that are 2 - to 4 - weeks in duration. Spaces are still available - don’t miss your chance to have an enriching summer experience. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

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[list][*]May 9th, 4:30pm PT/7:30pm ET, Casework 2: Overwhelming Evidence — A Text Adventure, a game where participants will work together to navigate the map, solve puzzles, and win! All are welcome.
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[*]May 20th, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 1 Math Jam, Problems 1 to 4, join the Canada/USA Mathcamp staff for this exciting Math Jam, where they discuss solutions to Problems 1 to 4 of the 2025 Mathcamp Qualifying Quiz!
[*]May 21st, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 2 Math Jam, Problems 5 and 6, Canada/USA Mathcamp staff will discuss solutions to Problems 5 and 6 of the 2025 Mathcamp Qualifying Quiz![/list]
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0 replies
jlacosta
May 1, 2025
0 replies
Interesting inequalities
sqing   0
7 minutes ago
Source: Own
Let $a,b,c \geq 0 $ and $ab+bc+ca- abc =3.$ Show that
$$a+k(b+c)\geq 2\sqrt{3 k}$$Where $ k\geq 1. $
Let $a,b,c \geq 0 $ and $2(ab+bc+ca)- abc =31.$ Show that
$$a+k(b+c)\geq \sqrt{62k}$$Where $ k\geq 1. $
0 replies
1 viewing
sqing
7 minutes ago
0 replies
Mega angle chase
kjhgyuio   1
N 33 minutes ago by jkim0656
Source: https://mrdrapermaths.wordpress.com/2021/01/30/filtering-with-basic-angle-facts/
........
1 reply
+1 w
kjhgyuio
38 minutes ago
jkim0656
33 minutes ago
Simple but hard
Lukariman   1
N 38 minutes ago by Giant_PT
Given triangle ABC. Outside the triangle, construct rectangles ACDE and BCFG with equal areas. Let M be the midpoint of DF. Prove that CM passes through the center of the circle circumscribing triangle ABC.
1 reply
Lukariman
2 hours ago
Giant_PT
38 minutes ago
Floor function and coprime
mofumofu   13
N an hour ago by Thapakazi
Source: 2018 China TST 2 Day 2 Q4
Let $k, M$ be positive integers such that $k-1$ is not squarefree. Prove that there exist a positive real $\alpha$, such that $\lfloor \alpha\cdot k^n \rfloor$ and $M$ are coprime for any positive integer $n$.
13 replies
mofumofu
Jan 9, 2018
Thapakazi
an hour ago
Minimum number of points
Ecrin_eren   2
N Yesterday at 8:32 PM by Shan3t
There are 18 teams in a football league. Each team plays against every other team twice in a season—once at home and once away. A win gives 3 points, a draw gives 1 point, and a loss gives 0 points. One team became the champion by earning more points than every other team. What is the minimum number of points this team could have?

2 replies
Ecrin_eren
Yesterday at 4:09 PM
Shan3t
Yesterday at 8:32 PM
Weird locus problem
Sedro   7
N Yesterday at 8:00 PM by ReticulatedPython
Points $A$ and $B$ are in the coordinate plane such that $AB=2$. Let $\mathcal{H}$ denote the locus of all points $P$ in the coordinate plane satisfying $PA\cdot PB=2$, and let $M$ be the midpoint of $AB$. Points $X$ and $Y$ are on $\mathcal{H}$ such that $\angle XMY = 45^\circ$ and $MX\cdot MY=\sqrt{2}$. The value of $MX^4 + MY^4$ can be expressed in the form $\tfrac{m}{n}$, where $m$ and $n$ are relatively prime positive integers. Find $m+n$.
7 replies
Sedro
May 11, 2025
ReticulatedPython
Yesterday at 8:00 PM
2024 Mock AIME 1 ** p15 (cheaters' trap) - 128 | n^{\sigma (n)} - \sigma(n^n)
parmenides51   3
N Yesterday at 6:17 PM by Sedro
Let $N$ be the number of positive integers $n$ such that $n$ divides $2024^{2024}$ and $128$ divides
$$n^{\sigma (n)} - \sigma(n^n)$$where $\sigma (n)$ denotes the number of positive integers that divide $n$, including $1$ and $n$. Find the remainder when $N$ is divided by $1000$.
3 replies
parmenides51
Jan 29, 2025
Sedro
Yesterday at 6:17 PM
IOQM P23 2024
SomeonecoolLovesMaths   3
N Yesterday at 4:53 PM by lakshya2009
Consider the fourteen numbers, $1^4,2^4,...,14^4$. The smallest natural numebr $n$ such that they leave distinct remainders when divided by $n$ is:
3 replies
SomeonecoolLovesMaths
Sep 8, 2024
lakshya2009
Yesterday at 4:53 PM
Inequalities
sqing   2
N Yesterday at 4:05 PM by MITDragon
Let $ 0\leq x,y,z\leq 2. $ Prove that
$$-48\leq (x-yz)( 3y-zx)(z-xy)\leq 9$$$$-144\leq (3x-yz)(y-zx)(3z-xy)\leq\frac{81}{64}$$$$-144\leq (3x-yz)(2y-zx)(3z-xy)\leq\frac{81}{16}$$
2 replies
sqing
May 9, 2025
MITDragon
Yesterday at 4:05 PM
Pells equation
Entrepreneur   0
Yesterday at 3:56 PM
A Pells Equation is defined as follows $$x^2-1=ky^2.$$Where $x,y$ are positive integers and $k$ is a non-square positive integer. If $(x_n,y_n)$ denotes the n-th set of solution to the equation with $(x_0,y_0)=(1,0).$ Then, prove that $$x_{n+1}x_n-ky_{n+1}y_n=x_1,$$$$x_n\pm y_n\sqrt k=(x_1\pm y_1\sqrt k)^n.$$
0 replies
Entrepreneur
Yesterday at 3:56 PM
0 replies
Incircle concurrency
niwobin   1
N Yesterday at 2:42 PM by niwobin
Triangle ABC with incenter I, incircle is tangent to BC, AC, and AB at D, E and F respectively.
DT is a diameter for the incircle, and AT meets the incircle again at point H.
Let DH and EF intersect at point J. Prove: AJ//BC.
1 reply
niwobin
May 11, 2025
niwobin
Yesterday at 2:42 PM
Inequalities
sqing   3
N Yesterday at 2:29 PM by rachelcassano
Let $ a,b,c>0 $ . Prove that
$$\frac{a+5b}{b+c}+\frac{b+5c}{c+a}+\frac{c+5a}{a+b}\geq 9$$$$ \frac{2a+11b}{b+c}+\frac{2b+11c}{c+a}+\frac{2c+11a}{a+b}\geq \frac{39}{2}$$$$ \frac{25a+147b}{b+c}+\frac{25b+147c}{c+a}+\frac{25c+147a}{a+b} \geq258$$
3 replies
sqing
May 14, 2025
rachelcassano
Yesterday at 2:29 PM
The centroid of ABC lies on ME [2023 Abel, Problem 1b]
Amir Hossein   3
N Yesterday at 1:45 PM by Captainscrubz
In the triangle $ABC$, points $D$ and $E$ lie on the side $BC$, with $CE = BD$. Also, $M$ is the midpoint of $AD$. Show that the centroid of $ABC$ lies on $ME$.
3 replies
Amir Hossein
Mar 12, 2024
Captainscrubz
Yesterday at 1:45 PM
2021 SMT Guts Round 5 p17-20 - Stanford Math Tournament
parmenides51   5
N Yesterday at 8:00 AM by MATHS_ENTUSIAST
p17. Let the roots of the polynomial $f(x) = 3x^3 + 2x^2 + x + 8 = 0$ be $p, q$, and $r$. What is the sum $\frac{1}{p} +\frac{1}{q} +\frac{1}{r}$ ?


p18. Two students are playing a game. They take a deck of five cards numbered $1$ through $5$, shuffle them, and then place them in a stack facedown, turning over the top card next to the stack. They then take turns either drawing the card at the top of the stack into their hand, showing the drawn card to the other player, or drawing the card that is faceup, replacing it with the card on the top of the pile. This is repeated until all cards are drawn, and the player with the largest sum for their cards wins. What is the probability that the player who goes second wins, assuming optimal play?


p19. Compute the sum of all primes $p$ such that $2^p + p^2$ is also prime.


p20. In how many ways can one color the $8$ vertices of an octagon each red, black, and white, such that no two adjacent sides are the same color?


PS. You should use hide for answers. Collected here.
5 replies
parmenides51
Feb 11, 2022
MATHS_ENTUSIAST
Yesterday at 8:00 AM
2011 JBMO Shortlist G2
parmenides51   5
N Oct 16, 2021 by REYNA_MAIN
Source: 2011 JBMO Shortlist G2
Let $AD,BF$ and ${CE}$ be the altitudes of $\vartriangle ABC$. A line passing through ${D}$ and parallel to ${AB}$intersects the line ${EF}$at the point ${G}$. If ${H}$ is the orthocenter of $\vartriangle ABC$, find the angle ${\angle{CGH}}$.
5 replies
parmenides51
Oct 8, 2017
REYNA_MAIN
Oct 16, 2021
2011 JBMO Shortlist G2
G H J
G H BBookmark kLocked kLocked NReply
Source: 2011 JBMO Shortlist G2
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parmenides51
30652 posts
#1 • 3 Y
Y by Adventure10, Mango247, Rounak_iitr
Let $AD,BF$ and ${CE}$ be the altitudes of $\vartriangle ABC$. A line passing through ${D}$ and parallel to ${AB}$intersects the line ${EF}$at the point ${G}$. If ${H}$ is the orthocenter of $\vartriangle ABC$, find the angle ${\angle{CGH}}$.
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MathsLion
113 posts
#2 • 2 Y
Y by Adventure10, Mango247
Please correct me if I'm wrong.
It's obvious that BECF and CFHD are cyclic. From GD||AB we have $\angle GDH=90 - $\angle ABC= $\angle GHF 
so points C, H, D, G, F are concyclic
 and $\angle CGH=90
This post has been edited 1 time. Last edited by MathsLion, Jun 8, 2018, 9:08 PM
Reason: I have problems with using Latex
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arc_ankon
93 posts
#3 • 4 Y
Y by Euclidean345, Ibnath2, Adventure10, Mango247
MathsLion wrote:
Please correct me if I'm wrong.
It's obvious that $BECF$ and $CFHD$ are cyclic. From $GD||AB$ we have $\angle GDH=90 - \angle ABC$= $\angle GHF$
so points $C, H, D, G, F$ are concyclic
and $\angle CGH=90$
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AlastorMoody
2125 posts
#4 • 2 Y
Y by Adventure10, Mango247
$$\angle BAD=\angle DEB=90^{\circ}-B=\angle ADG \text{ and } \angle HEG=180^{\circ}-(90^{\circ}-B)=90^{\circ}+B \implies DHEG \text{ is cyclic or } H \text{ passes through } (DEG)$$Now, Since, $$ AB||DG \text{ and Let } DG \cap CF=X \implies \angle FXG=90^{\circ} \implies \angle FGX=\angle C=\angle ECD \implies DEGC \text{ is cyclic or } C \text{ passes though } (DEG)$$Hence, $DHEGC$ is cyclic $\implies \angle HEC=\boxed{\angle CGH=90^{\circ}}$
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sttsmet
139 posts
#5
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Accually, the quadrilaterals ${HDFG}$ and ${HDCF}$ are cyclic, so the quadrilateral ${HDCG}$ is also cyclic. Finally, since ${\angle CDH=90^{\circ}}$ it will be ${\angle CGH=90^{\circ}}$
This post has been edited 1 time. Last edited by sttsmet, Jun 2, 2021, 11:04 AM
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REYNA_MAIN
41 posts
#6
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Storaij
This post has been edited 6 times. Last edited by REYNA_MAIN, Oct 16, 2021, 12:44 PM
Reason: hypesadnub done correcting errur
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