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Ankoganit   43
N 8 minutes ago by jasperE3
Source: India IMO Training Camp 2016, Practice test 2, Problem 2
Find all functions $f:\mathbb R\to\mathbb R$ such that $$f\left( x^2+xf(y)\right)=xf(x+y)$$for all reals $x,y$.
43 replies
Ankoganit
Jul 22, 2016
jasperE3
8 minutes ago
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Classical blackboard game: Find the invariant!
Tintarn   2
N Dec 10, 2024 by zaidova
Source: Baltic Way 2024, Problem 3
Positive real numbers $a_1, a_2, \ldots, a_{2024}$ are written on the blackboard. A move consists of choosing two numbers $x$ and $y$ on the blackboard, erasing them and writing the number $\frac{x^2+6xy+y^2}{x+y}$ on the blackboard. After $2023$ moves, only one number $c$ will remain on the blackboard. Prove that
\[
c<2024 (a_1+a_2+\ldots+a_{2024}).\]
2 replies
Tintarn
Nov 16, 2024
zaidova
Dec 10, 2024
Classical blackboard game: Find the invariant!
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Source: Baltic Way 2024, Problem 3
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Tintarn
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Positive real numbers $a_1, a_2, \ldots, a_{2024}$ are written on the blackboard. A move consists of choosing two numbers $x$ and $y$ on the blackboard, erasing them and writing the number $\frac{x^2+6xy+y^2}{x+y}$ on the blackboard. After $2023$ moves, only one number $c$ will remain on the blackboard. Prove that
\[
c<2024 (a_1+a_2+\ldots+a_{2024}).\]
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bin_sherlo
672 posts
#2
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Solution
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zaidova
84 posts
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$sketch$ $of$ $my$ $solution$
$\frac{x^2+6xy+y^2}{x+y}=\frac{(x+y)^2+4xy}{x+y}=(x+y)+\frac{4xy}{x+y}=(x+y)+\frac{4}{\frac{1}{x}+\frac{1}{y}}$
After induction we get invariance like:
$\frac{4}{\frac{1}{a_1}+\frac{1}{a_2}+\frac{1}{a_3}+...+\frac{1}{a_{2024}}}$ it has a same value for each $a_i$ ( it is constant, does not depend on the selection of the numbers). The main idea is this . Remain part is not hard . ($AM-HM$ or $C.S$ inequalities help)
This post has been edited 1 time. Last edited by zaidova, Dec 10, 2024, 8:33 PM
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