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Yet another way to reflect H to the circumcircle!
Tintarn   1
N 35 minutes ago by bin_sherlo
Source: Baltic Way 2024, Problem 14
Let $ABC$ be an acute triangle with circumcircle $\omega$. The altitudes $AD$, $BE$ and $CF$ of the triangle $ABC$ intersect at point $H$. A point $K$ is chosen on the line $EF$ such that $KH\parallel BC$. Prove that the reflection of $H$ in $KD$ lies on $\omega$.
1 reply
Tintarn
an hour ago
bin_sherlo
35 minutes ago
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