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Not so classic orthocenter problem
m4thbl3nd3r   4
N 4 minutes ago by hanzo.ei
Source: own?
Let $O$ be circumcenter of a non-isosceles triangle $ABC$ and $H$ be a point in the interior of $\triangle ABC$. Let $E,F$ be foots of perpendicular lines from $H$ to $AC,AB$. Suppose that $BCEF$ is cyclic and $M$ is the circumcenter of $BCEF$, $HM\cap AB=K,AO\cap BE=T$. Prove that $KT$ bisects $EF$
4 replies
m4thbl3nd3r
Yesterday at 4:59 PM
hanzo.ei
4 minutes ago
Chile TST IMO prime geo
vicentev   4
N 14 minutes ago by Retemoeg
Source: TST IMO CHILE 2025
Let \( ABC \) be a triangle with \( AB < AC \). Let \( M \) be the midpoint of \( AC \), and let \( D \) be a point on segment \( AC \) such that \( DB = DC \). Let \( E \) be the point of intersection, different from \( B \), of the circumcircle of triangle \( ABM \) and line \( BD \). Define \( P \) and \( Q \) as the points of intersection of line \( BC \) with \( EM \) and \( AE \), respectively. Prove that \( P \) is the midpoint of \( BQ \).
4 replies
vicentev
Today at 2:35 AM
Retemoeg
14 minutes ago
Cute orthocenter geometry
MarkBcc168   77
N 17 minutes ago by ErTeeEs06
Source: ELMO 2020 P4
Let acute scalene triangle $ABC$ have orthocenter $H$ and altitude $AD$ with $D$ on side $BC$. Let $M$ be the midpoint of side $BC$, and let $D'$ be the reflection of $D$ over $M$. Let $P$ be a point on line $D'H$ such that lines $AP$ and $BC$ are parallel, and let the circumcircles of $\triangle AHP$ and $\triangle BHC$ meet again at $G \neq H$. Prove that $\angle MHG = 90^\circ$.

Proposed by Daniel Hu.
77 replies
MarkBcc168
Jul 28, 2020
ErTeeEs06
17 minutes ago
A functional equation from MEMO
square_root_of_3   23
N 22 minutes ago by John_Mgr
Source: Middle European Mathematical Olympiad 2022, problem I-1
Find all functions $f: \mathbb R \to \mathbb R$ such that $$f(x+f(x+y))=x+f(f(x)+y)$$holds for all real numbers $x$ and $y$.
23 replies
square_root_of_3
Sep 1, 2022
John_Mgr
22 minutes ago
A weird inequality
Eeightqx   0
30 minutes ago
For all $a,\,b,\,c>0$, find the maximum $\lambda$ which satisfies
$$\sum_{cyc}a^2(a-2b)(a-\lambda b)\ge 0.$$hint
0 replies
Eeightqx
30 minutes ago
0 replies
Student's domination
Entei   0
34 minutes ago
Given $n$ students and their test results on $k$ different subjects, we say that student $A$ dominates student $B$ if and only if $A$ outperforms $B$ on all subjects. Assume that no two of them have the same score on the same subject, find the probability that there exists a pair of domination in class.
0 replies
Entei
34 minutes ago
0 replies
The Curious Equation for ConoSur
vicentev   3
N 41 minutes ago by AshAuktober
Source: TST IMO-CONO CHILE 2025
Find all triples \( (x, y, z) \) of positive integers that satisfy the equation
\[
x + xy + xyz = 31.
\]
3 replies
vicentev
an hour ago
AshAuktober
41 minutes ago
You just need to throw facts
vicentev   3
N 41 minutes ago by MathSaiyan
Source: TST IMO CHILE 2025
Let \( a, b, c, d \) be real numbers such that \( abcd = 1 \), and
\[
a + \frac{1}{a} + b + \frac{1}{b} + c + \frac{1}{c} + d + \frac{1}{d} = 0.
\]Prove that one of the numbers \( ab, ac \) or \( ad \) is equal to \( -1 \).
3 replies
vicentev
an hour ago
MathSaiyan
41 minutes ago
A number theory problem from the British Math Olympiad
Rainbow1971   5
N 42 minutes ago by Rainbow1971
Source: British Math Olympiad, 2006/2007, round 1, problem 6
I am a little surprised to find that I am (so far) unable to solve this little problem:

[quote]Let $n$ be an integer. Show that, if $2 + 2 \sqrt{1+12n^2}$ is an integer, then it is a perfect square.[/quote]

I set $k := \sqrt{1+12n^2}$. If $2 + 2 \sqrt{1+12n^2}$ is an integer, then $k (=\sqrt{1+12n^2})$ is at least rational, so that $1 + 12n^2$ must be a perfect square then. Using Conway's topograph method, I have found out that the smallest non-negative pairs $(n, k)$ for which this happens are $(0,1), (2,7), (28,97)$ and $(390, 1351)$, and that, for every such pair $(n,k)$, the "next" such pair can be calculated as
$$
\begin{bmatrix}
7 & 2 \\
24 & 7 
\end{bmatrix} \begin{bmatrix}
n \\
k 
\end{bmatrix}
.$$The eigenvalues of that matrix are irrational, however, so that any calculation which uses powers of that matrix is a little cumbersome. There must be an easier way, but I cannot find it. Can you?

Thank you.




5 replies
Rainbow1971
Yesterday at 8:39 PM
Rainbow1971
42 minutes ago
Finding maximum sum of consecutive ten numbers in circle.
Goutham   3
N an hour ago by FarrukhKhayitboyev
Each of $999$ numbers placed in a circular way is either $1$ or $-1$. (Both values appear). Consider the total sum of the products of every $10$ consecutive numbers.
$(a)$ Find the minimal possible value of this sum.
$(b)$ Find the maximal possible value of this sum.
3 replies
Goutham
Feb 8, 2011
FarrukhKhayitboyev
an hour ago
The Chile Awkward Party
vicentev   0
an hour ago
Source: TST IMO CHILE 2025
At a meeting, there are \( N \) people who do not know each other. Prove that it is possible to introduce them in such a way that no three of them have the same number of acquaintances.
0 replies
vicentev
an hour ago
0 replies
Sharygin CR P20
TheDarkPrince   37
N an hour ago by E50
Source: Sharygin 2018
Let the incircle of a nonisosceles triangle $ABC$ touch $AB$, $AC$ and $BC$ at points $D$, $E$ and $F$ respectively. The corresponding excircle touches the side $BC$ at point $N$. Let $T$ be the common point of $AN$ and the incircle, closest to $N$, and $K$ be the common point of $DE$ and $FT$. Prove that $AK||BC$.
37 replies
TheDarkPrince
Apr 4, 2018
E50
an hour ago
Fibonacci sequence and primes
vicentev   0
an hour ago
Source: TST IMO CHILE 2025
Let \( u_n \) be the \( n \)-th term of the Fibonacci sequence (where \( u_1 = u_2 = 1 \) and \( u_{n+1} = u_n + u_{n-1} \) for \( n \geq 2 \)). For each prime \( p \), let \( n(p) \) be the smallest integer \( n \) such that \( u_n \) is divisible by \( p \). Find the smallest possible value of \( p - n(p) \).
0 replies
vicentev
an hour ago
0 replies
circumcircle tangent to angle bisector
parmenides51   1
N Oct 3, 2018 by RagvaloD
Source: Sharygin 2010 Final 8.1
For a nonisosceles triangle $ABC$, consider the altitude from vertex $A$ and two bisectrices from remaining vertices. Prove that the circumcircle of the triangle formed by these three lines touches the bisectrix from vertex $A$.
1 reply
parmenides51
Oct 2, 2018
RagvaloD
Oct 3, 2018
circumcircle tangent to angle bisector
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Source: Sharygin 2010 Final 8.1
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parmenides51
30628 posts
#1 • 2 Y
Y by Adventure10, Mango247
For a nonisosceles triangle $ABC$, consider the altitude from vertex $A$ and two bisectrices from remaining vertices. Prove that the circumcircle of the triangle formed by these three lines touches the bisectrix from vertex $A$.
This post has been edited 1 time. Last edited by parmenides51, Apr 30, 2019, 7:19 PM
Reason: official formulation added
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RagvaloD
4887 posts
#2 • 2 Y
Y by Adventure10, Mango247
Point $I$ is point of intersection of bisectors and lies in the circumcircle, so we need to show, that $OI \perp AI$
Easy to prove with angle chasing, that $\angle EIA= 90-\frac{\angle B}{2},\angle GOI=180-\angle B \to \angle OIG=\frac{\angle B}{2}$ so $\angle OIA=90$
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