1954 AHSME Problems/Problem 24

Problem 24

The values of $k$ for which the equation $2x^2-kx+x+8=0$ will have real and equal roots are:

$\textbf{(A)}\ 9\text{ and }-7\qquad\textbf{(B)}\ \text{only }-7\qquad\textbf{(C)}\ \text{9 and 7}\\ \textbf{(D)}\ -9\text{ and }-7\qquad\textbf{(E)}\ \text{only 9}$

Solution

$b^2-4ac=0\implies b^2=4ac\implies (1-k)^2=4(2)(8)\implies (1-k)^2=8^2\implies 1-k=8\implies k=-7, 1-k=-8\implies k=9$, $\fbox{A}$

See Also

1954 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 23
Followed by
Problem 25
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