1958 AHSME Problems/Problem 1

Problem

The value of $[2 - 3(2 - 3)^{-1}]^{-1}$ is:

$\textbf{(A)}\ 5\qquad  \textbf{(B)}\ -5\qquad  \textbf{(C)}\ \frac{1}{5}\qquad  \textbf{(D)}\ -\frac{1}{5}\qquad  \textbf{(E)}\ \frac{5}{3}$

Solution

$\frac{1}{2-3(-1)}=\frac{1}{5}$, so the answer is $\boxed{\text{C}}$.

See also

1958 AHSC (ProblemsAnswer KeyResources)
Preceded by
First question
Followed by
Problem 2
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