1958 AHSME Problems/Problem 34

Problem

The numerator of a fraction is $6x + 1$ , then denominator is $7 - 4x$ , and $x$ can have any value between $-2$ and $2$ , both included. The values of $x$ for which the numerator is greater than the denominator are:

$\textbf{(A)}\ \frac{3}{5} < x \le 2\qquad \textbf{(B)}\ \frac{3}{5} \le x \le 2\qquad \textbf{(C)}\ 0 < x \le 2\qquad \\ \textbf{(D)}\ 0 \le x \le 2\qquad \textbf{(E)}\ -2 \le x \le 2$

Solution

$\fbox{}$

1958 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 33	Followed by Problem 35
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1958 AHSME Problems/Problem 34

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