1963 AHSME Problems/Problem 14
Problem
Given the equations and . If, when the roots of the equation are suitably listed, each root of the second equation is more than the corresponding root of the first equation, then equals:
Solution
Let the two roots of be and . By Vieta's Formulas, Each root of is five more than each root of the original, so using Vieta's Formula again yields Substitute to get The answer is .
See Also
1963 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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