1963 AHSME Problems/Problem 33
Problem 33
Given the line and a line parallel to the given line and units from it. A possible equation for is:
Solution
If a point on line is four units away from another line, the perpendicular distance between the two lines is . Since a line perpendicular to the original has a slope of , a point on that line is units away and can be derived from subtracting from the y-coordinate and adding to the x-coordinate of a point on the original line.
We want the perpendicular distance to be , so . Since one point on the original line is , a point on line will be , which is simplified as . Using point-slope form, the equation of line is The answer is .
See Also
1963 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 32 |
Followed by Problem 34 | |
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