1965 AHSME Problems/Problem 37
Problem
Point is selected on side of in such a way that and point is selected on side such that . The point of intersection of and is . Then is:
Solution
We use mass points for this problem. Let denote the mass of point . Rewrite the expression we are finding as Now, let . We then have , so , and We can let . We have From here, substitute the respective values to get
This answer corresponds to .
~JustinLee2017
See Also
1965 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 36 |
Followed by Problem 38 | |
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