1970 AHSME Problems/Problem 11
Problem
If two factors of are and , the value of is
Solution
From the Remainder Theorem, we have and . Simplifying both of those equations gives and . Since and , we set those equal to get:
This gives when substituting back into either of the two equations, and , which is answer .
See also
1970 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
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