1970 AHSME Problems/Problem 29

Problem

It is now between 10:00 and 11:00 o'clock, and six minutes from now, the minute hand of a watch will be exactly opposite the place where the hour hand was three minutes ago. What is the exact time now?

$\text{(A) } 10:05\tfrac{5}{11}\quad \text{(B) } 10:07\tfrac{1}{2}\quad \text{(C) } 10:10\quad \text{(D) } 10:15\quad \text{(E) } 10:17\tfrac{1}{2}$

Solution

$\fbox{D}$ 50 + (m-3)/12 = 30 + (m+6) = 10hours + m = 10: 15

See also

1970 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 28
Followed by
Problem 30
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