1970 AHSME Problems/Problem 30
Problem
In the accompanying figure, segments and are parallel, the measure of angle is twice that of angle , and the measures of segments and are and respectively. Then the measure of is equal to
Solution
With reference to the diagram above, let be the point on such that . Let . We then have since , so , which means is isosceles.
Therefore, , hence our answer is .
See also
1970 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 29 |
Followed by Problem 31 | |
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