1980 AHSME Problems/Problem 1

Problem 1

The largest whole number such that seven times the number is less than $100$ is

$\text{(A)} \ 12 \qquad \text{(B)} \ 13 \qquad \text{(C)} \ 14 \qquad \text{(D)} \ 15 \qquad \text{(E)} \ 16$

Solution

Let $x$ be a whole number such that $7x < 100$ . Dividing by $7$ yields $x < \frac{100}{7} = 14\dfrac{2}{7}$ , so $x = \boxed{(\textbf{C})\ 14}$ is the maximum possible value.

1980 AHSME (Problems • Answer Key • Resources)
Preceded by First question	Followed by Problem 2
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All AHSME Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.

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1980 AHSME Problems/Problem 1

Problem 1

Solution

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