1980 AHSME Problems/Problem 1

Problem 1

The largest whole number such that seven times the number is less than $100$ is

$\text{(A)} \ 12 \qquad \text{(B)} \ 13 \qquad \text{(C)} \ 14 \qquad \text{(D)} \ 15 \qquad \text{(E)} \ 16$

Solution

Let $x$ be a whole number such that $7x < 100$. Dividing by $7$ yields $x < \frac{100}{7} =  14\dfrac{2}{7}$, so $x = \boxed{(\textbf{C})\ 14}$ is the maximum possible value.

See also

1980 AHSME (ProblemsAnswer KeyResources)
Preceded by
First question
Followed by
Problem 2
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