1980 AHSME Problems/Problem 27
Problem
The sum equals
Solution
Lets set our original expression equal to . So . Cubing this gives us So we have . We can easily see that 1 is a root of this polynomial. By synthetic division, the new polynomial is , which has no real roots. Thus . Since 1 is not A-D, our answer is .
See also
1980 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 26 |
Followed by Problem 28 | |
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