1986 AIME Problems/Problem 10
Problem
In a parlor game, the magician asks one of the participants to think of a three digit number where , , and represent digits in base in the order indicated. The magician then asks this person to form the numbers , , , , and , to add these five numbers, and to reveal their sum, . If told the value of , the magician can identify the original number, . Play the role of the magician and determine if .
Solution
Solution 1
Let be the number . Observe that so
This reduces to one of . But also so . Recall that refer to the digits the three digit number , so of the four options, only satisfies this inequality.
Solution 2
As in Solution 1, , and so as above we get . We can also take this equation modulo ; note that , so
Therefore is mod and mod . There is a shared factor in in both, but the Chinese Remainder Theorem still tells us the value of mod , namely mod . We see that there are no other 3-digit integers that are mod , so .
Solution 3
Let then Since , we get the inequality Checking each of the multiples of from to by subtracting from each , we quickly find
~ Nafer
Solution 4
The sum of the five numbers is We can see that （mod ） and （mod ） so we need to make sure that （mod ） by some testing. So we let
Then, we know that so only lie in the interval
When we test , impossible
When we test
When we test , well, it's impossible
The answer is then
~bluesoul
See also
1986 AIME (Problems • Answer Key • Resources) | ||
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Followed by Problem 11 | |
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