1988 AHSME Problems/Problem 4

Problem

The slope of the line $\frac{x}{3} + \frac{y}{2} = 1$ is

$\textbf{(A)}\ -\frac{3}{2}\qquad \textbf{(B)}\ -\frac{2}{3}\qquad \textbf{(C)}\ \frac{1}{3}\qquad \textbf{(D)}\ \frac{2}{3}\qquad \textbf{(E)}\ \frac{3}{2}$


Solution

To find the slope, all we have to do is put the equation into slope-intercept form. We subtract $\frac{x}{3}$ from both sides and then multiple all terms by $2$. This yields $y=-\frac{2}{3}x+1$, so the slope is $-\frac{2}{3} \implies \boxed{\text{B}}$.

See also

1988 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
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