1996 AJHSME Problems/Problem 12
Contents
Problem 12
What number should be removed from the list so that the average of the remaining numbers is ?
Solution 1
Adding all of the numbers gives us as the current total. Since there are numbers, the current average is . We need to take away a number from the total and then divide the result by because there will only be numbers left to give an average of . Setting up the equation:
Thus, the answer is
Solution 2
Similar to the first solution, the current total is . Since there are numbers on the list, taking number away will leave numbers. If those numbers have an average of , then those numbers must have a sum of . Thus, the number that was removed must be , and the answer is .
See Also
1996 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
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