1996 AJHSME Problems/Problem 2
Problem
Jose, Thuy, and Kareem each start with the number 10. Jose subtracts 1 from the number 10, doubles his answer, and then adds 2. Thuy doubles the number 10, subtracts 1 from her answer, and then adds 2. Kareem subtracts 1 from the number 10, adds 2 to his number, and then doubles the result. Who gets the largest final answer?
Solution
Jose gets , then , then .
Thuy gets , then , and then .
Kareem gets , then , and then .
Thus, Kareem gets the highest number, and the answer is .
See also
1996 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
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All AJHSME/AMC 8 Problems and Solutions |
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