1999 AMC 8 Problems/Problem 16

Problem

Tori's mathematics test had 75 problems: 10 arithmetic, 30 algebra, and 35 geometry problems. Although she answered 70% of the arithmetic, 40% of the algebra, and 60% of the geometry problems correctly, she did not pass the test because she got less than 60% of the problems right. How many more problems would she have needed to answer correctly to earn a 60% passing grade?

$\text{(A)}\ 1 \qquad \text{(B)}\ 5 \qquad \text{(C)}\ 7 \qquad \text{(D)}\ 9 \qquad \text{(E)}\ 11$

Solution

First, calculate how many of each type of problem she got right:

Arithmetic: $70\% \cdot 10 = 0.70 \cdot 10 = 7$

Algebra: $40\% \cdot 30 = 0.40 \cdot 30 = 12$

Geometry: $60\% \cdot 35 = 0.60 \cdot 35 =  21$

Altogether, Tori answered $7 + 12 + 21 = 40$ questions correct. To get a $60\%$ on her test overall, she needed to get $60\% \cdot 75 = 0.60 \cdot 75 = 45$ questions right.

Therefore, she needed to answer $45 - 40 = 5$ more questions to pass, and the the correct answer is $\boxed{B}$

See Also

1999 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 15
Followed by
Problem 17
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Invalid username
Login to AoPS