2007 AMC 8 Problems/Problem 15
Contents
[hide]Problem
Let and be numbers with . Which of the following is impossible?
Solution
According to the given rules, every number needs to be positive. Since is always greater than , adding a positive number () to will always make it greater than .
Therefore, the answer is
Solution 2
We can test numbers into the inequality we’re given. The simplest is . We can see that , so is correct.
—jason.ca
Video Solution by WhyMath
~savannahsolver
Video Solution
https://www.youtube.com/watch?v=_ZHS4M7kpnE
Video Solution 2
https://youtu.be/GxR1giTQeD0 Soo, DRMS, NM
Video Solution by SpreadTheMathLove
https://www.youtube.com/watch?v=omFpSGMWhFc
See Also
2007 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
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All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.