2015 AMC 10A Problems/Problem 23
Contents
Problem
The zeroes of the function are integers. What is the sum of the possible values of
Solution 1
By Vieta's Formula, is the sum of the integral zeros of the function, and so is integral.
Because the zeros are integral, the discriminant of the function, , is a perfect square, say . Then adding 16 to both sides and completing the square yields Therefore and Let and ; then, and so . Listing all possible pairs (not counting transpositions because this does not affect (), , yields . These sum to , so our answer is .
Solution 2
Let and be the integer zeroes of the quadratic. Since the coefficient of the term is , the quadratic can be written as
By comparing this with ,
Plugging the first equation in the second, Rearranging gives These factors can be or
We want the number of distinct , and these factors gives . So the answer is .
Video Solution by Richard Rusczyk
https://artofproblemsolving.com/videos/amc/2015amc10a/397
Video Solution
~savannahsolver
See Also
2015 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 22 |
Followed by Problem 24 | |
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