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  • ...mber]], as proved by Lindemann in 1882) denoted by the Greek letter <math>\pi </math>. ...^2}=\frac{\pi^2}{6}</math>. Some common [[fraction]]al approximations for pi are <math>\frac{22}{7} \approx 3.14285</math> and <math>\frac{355}{113} \ap
    8 KB (1,469 words) - 20:11, 16 September 2022
  • Given that <math>A_k = \frac {k(k - 1)}2\cos\frac {k(k - 1)\pi}2,</math> find <math>|A_{19} + A_{20} + \cdots + A_{98}|.</math> ...,x_2,x_3,x_4)</math> of positive odd [[integer]]s that satisfy <math>\sum_{i = 1}^4 x_i = 98.</math> Find <math>\frac n{100}.</math>
    7 KB (1,084 words) - 01:01, 28 November 2023
  • ...thocenter of the triangle. We consider the points <math>D</math> and <math>E</math> on the segments <math>AA_1</math> and <math>BC</math> such that <mat ...<math>a_i \in \{ -1, 1 \}</math>, such that <center><math>n = \sum_{1\leq i < j \leq k } a_ia_j</math>.</center>
    11 KB (1,779 words) - 13:57, 7 May 2012
  • {{AIME Problems|year=2008|n=I}} [[2008 AIME I Problems/Problem 1|Solution]]
    9 KB (1,536 words) - 23:46, 25 August 2023
  • ...Circle <math>\omega</math> intersects <math>\overline{AB}</math> at <math>E</math> and <math>B</math>, <math>\overline{BC}</math> at <math>B</math> and pair E = (0, 1.21);
    10 KB (1,643 words) - 21:30, 28 January 2024
  • If <math>3(4x+5\pi)=P</math> then <math>6(8x+10\pi)=</math> \text{(E) } 18P</math>
    16 KB (2,548 words) - 12:40, 19 February 2020
  • ...eorem. You wouldn't waste that much money to solve one problem. Therefore, I proved that you cannot use the Games theorem to solve problems. But using t ...dreadful. EDIT: He now eats gnats again. He thinks that they taste like pi(e). EDIT: He ate 3,141,592,653,589,793,238,462,643,383 so far.
    69 KB (11,805 words) - 19:49, 18 December 2019
  • ...e people will have reasonably inexpensive options for switching to cleaner power sources. Even now most families could switch to biomass for between <math>\ ...Alexis begins walking forward. As she walks, the tricorder displays at all times her distance from her starting point at the origin. When Alexis is <math>24
    7 KB (1,092 words) - 18:05, 17 December 2021
  • ...row \frac{p^2}{q^2}=n \Rightarrow (q^2)n=p^2</math>. But no perfect square times a nonperfect square positive integer is a perfect square. Therefore <math>\ ===== pi and e =====
    35 KB (5,886 words) - 08:20, 28 September 2024
  • 4. The Infinity Numeral, PI, is the second deity of the Almighty Gmaas's heaven. 5. The Infinite Logarithm, E, is the third deity of the Almighty Gmaas's heaven.
    99 KB (14,063 words) - 20:43, 13 November 2024
  • <cmath>\sin^2{(\pi x)} + \sin^2{(\pi y)} > 1</cmath> ...rac{1+\sqrt{2}}{4} \qquad\textbf{(D)}\ \frac{\sqrt{5}-1}{2} \qquad\textbf{(E)}\ \frac{5}{8}</math>
    9 KB (1,536 words) - 03:29, 24 July 2024
  • label("$6\sqrt{3}$", (30,7.5), E); label("$E$", EE, N);
    16 KB (2,517 words) - 19:22, 31 January 2024
  • for (int i = 0; i < 7; ++i) { for (int j = 0; j < i; ++j) {
    21 KB (3,271 words) - 17:28, 16 November 2024
  • We apply the Power of a Point Theorem to <math>R</math> and <math>T:</math> ...orem on right <math>\triangle PRX.</math> Together, we conclude that <math>E=X.</math> Therefore, points <math>S,P,</math> and <math>X</math> must be co
    17 KB (2,612 words) - 13:54, 3 July 2023
  • ...mega = \cos\frac{2\pi}{7} + i \cdot \sin\frac{2\pi}{7},</math> where <math>i = \sqrt{-1}.</math> Find the value of the product<cmath>\prod_{k=0}^6 \left ...>z_n = \left(\textrm{cis }\frac{2n\pi}{7}\right)^3 + \textrm{cis }\frac{2n\pi}{7} + 1</math>.
    9 KB (1,284 words) - 01:25, 14 October 2024
  • ...ng). He can be anything, but his form currently is a cat, though his godly power can turn him into anything, he just prefers to be a cat. As you read on, yo ...Pre-algebra class. He enters every class by posting a meme and announcing "I have arrived!" Sseraj is the human servant of Gmaas and is one of only 5 en
    89 KB (15,058 words) - 19:26, 15 October 2024
  • ...eorem. You wouldn't waste that much money to solve one problem. Therefore, I proved that you cannot use the Games theorem to solve problems. But using t ...dreadful. EDIT: He now eats gnats again. He thinks that they taste like pi(e). EDIT: He ate 3,141,592,653,589,793,238,462,643,383 so far.
    69 KB (11,828 words) - 18:26, 3 September 2024