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- ...y=a(x-h)^2+k</math> where a, h, and k are constants and the [[vertex]] is (h,k). This is very useful for graphing the quadratic because the vertex and s ...ath>x</math> term is squared, and horizontal if the <math>y</math> term is squared. The graph will be oriented (opens up) upwards/right if <math>a</math> is p3 KB (551 words) - 16:22, 13 September 2023
- ...lculation using that the ratio of areas is equal to the ratio of the sides squared), ...the trapezoid is <math>\frac{39+52}{2} \cdot h = \frac{91}{2} h</math>. So h divides 2. Let <math>x</math> be <math>2h</math>. The area is now <math>91x8 KB (1,308 words) - 07:05, 19 December 2022
- ...htarrow \frac ab</math> maximizes at <math>\frac 2{\sqrt {3}}</math>. This squared is <math>(\frac 2{\sqrt {3}})^2 = \frac4{3}</math>, and <math>4 + ...d it's x-coordinate is a, which is to the right of the vertex of the <math>H</math>, which is <math>\sqrt{a^2 - b^2}</math>. So for the intersection to8 KB (1,387 words) - 11:56, 29 January 2024
- ...oms as <math>h</math>, in general, we need numbers all the way up to <math>h\cdot 67^2</math>, so obviously, <math>67^2</math> is the smallest such numb The answer is 4489.(67 squared)12 KB (2,338 words) - 20:30, 13 February 2024
- ...ng this problem, we can play with the answers. The ratios of the altitudes squared is the ratio of the surface areas, so the answer choice has to be larger th ...sed the fact that the ratio of surface area is the ratio of side lengths ''squared''. However, with this, we can go two ways.4 KB (616 words) - 13:52, 4 April 2024
- The area of rectangle <math>ABCD</math> is <math>72</math> units squared. If point <math>A</math> and the midpoints of <math> \overline{BC} </math> ...t get the above answer. Label <math>AB = CD = l</math> and <math>BC = DA = h</math>3 KB (484 words) - 13:59, 22 October 2023
- pair G=(2/sqrt(3))*A,H=(2/sqrt(3))*B,I=(2/sqrt(3))*C,J=(2/sqrt(3))*D,K=(2/sqrt(3))*E,L=(2/sqrt(3)) draw(G--H--I--J--K--L--G);1 KB (195 words) - 18:22, 16 January 2023
- ...gure on the right. The box has base length <math>w</math> and height <math>h</math>. What is the area of the sheet of wrapping paper? <math>\textbf{(A) } 2(w+h)^2 \qquad \textbf{(B) } \frac{(w+h)^2}2 \qquad \textbf{(C) } 2w^2+4wh \qquad \textbf{(D) } 2w^2 \qquad \textbf6 KB (974 words) - 00:28, 30 May 2023
- .... The equation is <math>(8)(12)=(10)(h)</math>, which leaves us with <math>h=9.6</math>. We then solve for the length <math>\overline{AF}</math>, which ...that <math>GC^2 = \Big(x + \frac{10-x}{2}\Big)^2</math> (leave everything squared so that it cancels nicely at the end). By Pythagorean Theorem on Triangle <14 KB (2,247 words) - 20:07, 12 January 2024
- ...them because that makes no more square roots. So <math>\sqrt{x+3}=5</math> squared is <math>x+3=25</math> which tells us that <math>x</math> is <math>22</math ...uation of the second degree, meaning it contains at least one term that is squared. The standard form is <math>ax^2 + bx + c = 0</math> with <math>a</math>, <35 KB (5,882 words) - 18:08, 28 June 2021
- pair O, A, B, C, D, F, G, H, I, P, X; H = rotate(-120, G) * ((F + G) / 2);9 KB (1,380 words) - 16:12, 2 January 2024
- pair A,B,C,D,M,H; real xb=71, xd=121; ...int(D,A,B), D1=bisectorpoint(C,D,A), Bp=IP(CR(A,2),A--H), Cp=IP(CR(D,3),D--H);14 KB (2,254 words) - 18:26, 8 February 2024
- <math>V=\pi{r^2}h</math> ...nd <math>\cos\theta</math> for some <math>\theta</math> and the sum of the squared distances is <math>\sin^{2}\theta+\cos^{2}\theta=1</math>, as shown.4 KB (697 words) - 17:07, 24 March 2023
- .../math>. So now the problem boils down to how many distinct triplets <math>(h,i,j)</math> can be formed by taking the product of <math>n</math> dice valu ...r of <math>5</math>'s our product will have. Then how many different <math>h</math> values for the powers of <math>2</math> are possible?13 KB (2,194 words) - 19:10, 18 December 2023
