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- == Problem ==2 KB (402 words) - 13:54, 25 June 2023
- == Problem ==878 bytes (143 words) - 19:56, 1 April 2017
- == Problem == ...{4} \le 250</math>, so we have <math>n+1 = 4, 4 \cdot 3^2, \ldots, 4 \cdot 13^2, 4\cdot 3^2 \cdot 5^2</math>.10 KB (1,702 words) - 21:23, 25 July 2024
- == Problem ==3 KB (447 words) - 02:49, 16 January 2021
- == Problem == ...{(A) \ } 12\pi\qquad \mathrm{(B) \ } \frac{25\pi}{2}\qquad \mathrm{(C) \ } 13\pi\qquad \mathrm{(D) \ } \frac{27\pi}{2}\qquad\mathrm{(E) \ } 14\pi</math>1 KB (184 words) - 12:57, 19 January 2021
- == Problem ==1 KB (203 words) - 18:57, 24 December 2020
- == Problem ==1 KB (207 words) - 08:39, 25 July 2023
- == Problem == ...olutions so <math>P(x)</math> is at least quadratic. Let us first try this problem out as if <math>P(x)</math> is a quadratic polynomial. Thus <math>P(n)-(n+34 KB (642 words) - 01:14, 1 June 2024
- == Problem == ...assign to <math>(0,1,0)</math>. (We will see how this correlates with the problem.) Then define for each lattice point <math>(i,j)</math> its triplet thus:5 KB (897 words) - 23:21, 28 July 2022
- == Problem ==2 KB (298 words) - 19:02, 4 July 2013
- == Problem ==3 KB (486 words) - 21:15, 7 April 2023
- == Problem ==6 KB (1,083 words) - 20:10, 10 January 2025
- == Problem == Find the value of <math>10\cot(\cot^{-1}3+\cot^{-1}7+\cot^{-1}13+\cot^{-1}21).</math>3 KB (473 words) - 11:06, 18 December 2018
- == Problem ==5 KB (795 words) - 21:27, 19 December 2024
- == Problem ==4 KB (772 words) - 20:09, 7 May 2024
- == Problem == Thus, our problem can be restated: What is the probability that in a sequence of 31 distinct8 KB (1,269 words) - 09:55, 26 June 2024
- == Problem == ...erefore, <math>c_{14} = - 2</math>. Undergoing a similar process, <math>c_{13} = 3</math>, <math>c_{12} = - 5</math>, <math>c_{11} = 8</math>, and we see10 KB (1,595 words) - 15:30, 24 August 2024
- == Problem ==2 KB (274 words) - 03:07, 17 December 2023
- == Problem ==5 KB (762 words) - 00:18, 10 February 2023
- == Problem == ...{(B) } \frac{13}{14}\qquad \textbf{(C) }1 \qquad \textbf{(D) \ } \frac{14}{13}\qquad \textbf{(E) } \frac{7}{6} </math>1 KB (182 words) - 13:11, 26 January 2022
Page text matches
- <cmath>5-12-13</cmath> <cmath>10-24-26 = (5-12-13)*2</cmath>6 KB (943 words) - 09:44, 17 January 2025
- == Problem == <math>\textbf{(A)}\ 13\qquad\textbf{(B)}\ 26\qquad\textbf{(C)}\ 102\qquad\textbf{(D)}\ 103\qquad\t967 bytes (143 words) - 02:18, 27 June 2023
- == Problem == label("$3/2$",(0,13/4),dir(180));8 KB (1,016 words) - 23:17, 30 December 2023
- == Problem == {{AMC10 box|year=2016|ab=A|num-b=11|num-a=13}}2 KB (302 words) - 00:57, 18 October 2024
- *ten problems are projected one at a time on a screen. The time limit per problem is 3 minutes. *No team may submit more than one answer for any problem.8 KB (1,182 words) - 13:26, 3 April 2024
- ==Problem== 3+4+6=\boxed{13}1 KB (193 words) - 20:13, 18 May 2021
- \\frac{x+5-13}{x+5}+4&\ge 3 \1-\frac{13}{x+5}+4&\ge 312 KB (1,806 words) - 05:07, 19 June 2024
- ...n mathematics and also to help middle school students learn [[mathematical problem solving]]. ...oice|difficulty=1 - 1.5|breakdown=<u>Problems 1 - 12</u>: 1<br><u>Problems 13 - 25</u>: 1.5}}4 KB (584 words) - 23:33, 15 January 2025
- ...he largest area that this triangle can have? ([[1992 AIME Problems/Problem 13|AIME 1992]]) ...ntegers. Find <math>r+s</math>. (Solution [[Problems Collection|here]] see problem 3 solution 1)3 KB (583 words) - 20:20, 2 August 2024
- ([[2000 AMC 12/Problem 6|Source]]) ==Problem 1==4 KB (682 words) - 12:13, 8 December 2024
- ...d only once. In particular, memorizing a formula for PIE is a bad idea for problem solving. ==== Problem ====9 KB (1,703 words) - 00:20, 7 December 2024
- * <math>13! = 6227020800</math> ([[2007 iTest Problems/Problem 6|Source]])10 KB (809 words) - 15:40, 17 March 2024
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AIME II Problems/Problem 1]]1 KB (133 words) - 11:32, 22 March 2011
- draw(graph(f,(7+2*sqrt(13))/3,(7-2*sqrt(13))/3),red+linewidth(1)); ...style="text-align:right;">([[2006 AMC 10A Problems/Problem 8|2006 AMC 10A, Problem 8]])</div>3 KB (551 words) - 15:22, 13 September 2023
- * [[1991 AIME Problems/Problem 12]] * [[2001 AIME I Problems/Problem 13]]1 KB (179 words) - 18:41, 3 January 2025
- ...th>\{-2, 3, 6\}</math> we would be trying to calculate <math>\frac 3{\frac 13 + \frac 16 - \frac 12} = \frac 30</math>, which is obviously problematic. * [[2002 AMC 12A Problems/Problem 11]]1 KB (196 words) - 23:49, 5 January 2021
- ...d with addition. We see one instance of this in the divisibility rule for 13: we could multiply by 9 and subtract rather than multiplying by 4 and addin === Divisibility Rule for 13 ===10 KB (1,572 words) - 21:11, 22 September 2024
- This is a problem where constructive counting is not the simplest way to proceed. This next e ...proceed with the construction. If we were to go like before and break the problem down by each box, we'd get a fairly messy solution.13 KB (2,018 words) - 14:31, 10 January 2025
- * [[2020 AMC 10A Problems/Problem 24]] * [[1985 AIME Problems/Problem 13]]6 KB (923 words) - 16:39, 30 September 2024
- * [[Mock_AIME_2_2006-2007_Problems#Problem_8 | Mock AIME 2 2006-2007 Problem 8]] ([[number theory]]) *[[1994_AIME_Problems/Problem 9|1994 AIME Problem 9]]2 KB (316 words) - 15:03, 1 January 2024