2024 AMC 10A Problems/Problem 9
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Problem
In how many ways can juniors and seniors form disjoint teams of people so that each team has juniors and seniors?
Solution
The number of ways in which we can choose the juniors for the team are . Similarly, the number of ways to choose the seniors are the same, so the total is . But we must divide the number of permutations of three teams, which is . Thus the answer is .
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Video Solution 1 by Power Solve
https://youtu.be/j-37jvqzhrg?si=IBSPzNSvdIodGvZ7&t=1145
See also
2024 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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