Difference between revisions of "2019 AIME I Problems/Problem 8"
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==Problem 8== | ==Problem 8== | ||
==Solution(BASH)== | ==Solution(BASH)== | ||
− | + | NOT ALLOWED! | |
==Solution 2 (Another BASH)== | ==Solution 2 (Another BASH)== |
Revision as of 19:25, 14 March 2019
The 2019 AIME I takes place on March 13, 2019.
Problem 8
Solution(BASH)
NOT ALLOWED!
Solution 2 (Another BASH)
First, for simplicity, let and
. Note that
. We then bash the rest of the problem out. Take the tenth power of this expression and get
. Note that we also have
. So, it suffices to compute
. Let
. We have from cubing
that
or
. Next, using
, we get
or
. Solving gives
or
. Clearly
is extraneous, so
. Now note that
, and
. Thus we finally get
, giving
.
- Emathmaster
See Also
2019 AIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.