Difference between revisions of "2018 AMC 8 Problems/Problem 1"

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Also, you can note that <math>20\cdot14</math> is <math>280</math>, and that <math>20\cdot15</math> is <math>300</math>. Since <math>289</math> is closer to <math>280</math>, the answer is <math>\boxed{\textbf{(A)}14}</math> ~ Mathscienceclass
 
Also, you can note that <math>20\cdot14</math> is <math>280</math>, and that <math>20\cdot15</math> is <math>300</math>. Since <math>289</math> is closer to <math>280</math>, the answer is <math>\boxed{\textbf{(A)}14}</math> ~ Mathscienceclass
(Vishal Vinjamuri)
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Sruthi is doodoo
  
 
==See Also==
 
==See Also==

Revision as of 23:38, 18 June 2019

Problem 1

An amusement park has a collection of scale models, with ratio $1 : 20$, of buildings and other sights from around the country. The height of the United States Capitol is 289 feet. What is the height in feet of its replica to the nearest whole number?

$\textbf{(A) }14\qquad\textbf{(B) }15\qquad\textbf{(C) }16\qquad\textbf{(D) }18\qquad\textbf{(E) }20$

Solution 1

You can set up a ratio: $\frac{1}{20}=\frac{x}{289}$. Cross multiplying, you get $20x=289$. You divide by 20 to get $x=14.45$. The closest integer is $\boxed{\textbf{(A)}14}$

Solution 2

Also, you can note that $20\cdot14$ is $280$, and that $20\cdot15$ is $300$. Since $289$ is closer to $280$, the answer is $\boxed{\textbf{(A)}14}$ ~ Mathscienceclass Sruthi is doodoo

See Also

2018 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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