Difference between revisions of "2018 AMC 8 Problems/Problem 17"

Revision as of 16:53, 19 October 2019

Problem 17

Bella begins to walk from her house toward her friend Ella's house. At the same time, Ella begins to ride her bicycle toward Bella's house. They each maintain a constant speed, and Ella rides 5 times as fast as Bella walks. The distance between their houses is $2$ miles, which is $10,560$ feet, and Bella covers $2 \tfrac{1}{2}$ feet with each step. How many steps will Bella take by the time she meets Ella?

$\textbf{(A) }704\qquad\textbf{(B) }845\qquad\textbf{(C) }1056\qquad\textbf{(D) }1760\qquad \textbf{(E) }3520$

Solution

Since Ella rides 5 times as fast as Bella, Ella rides at a rate of $\frac{25}{2}$ or $12 \tfrac{1}{2}$ . Together, they move $15$ feet towards each other every unit. Dividing $10560$ by $15$ to find the number of steps Bella takes results in the answer of $\boxed{\textbf{(A) }704}$

Solution 2

Since Ella rides 5 times faster than Bella, the ratio of their speeds is 5:1. This means that Bella travels 1/6 of the way, and 1/6 of 10560 feet is 1760 feet. Bella also walks 2.5 feet in a step, and 1760 divided by 2.5 is $\boxed{\textbf{(A) }704}$ .

Solution 3

We know that Ella's speed is 12.5 st/s (steps per second) and Bella's speed is 2.5 st/s. Let the speeds in which they are walking and riding at be the slope of two equations, one for Bella and one for Ella. We make s the amount of steps she takes and d distance from their houses. Since we are finding where they meet, we need to solve for the intersections of the two equations for Ella and Bella. The equations we get are:

d = -12.5s + 10560

d = 2.5s

Subtracting both equations from each other gives us:

-15s + 10560 = 0

Solving that equation grants us:

s = 704

Since we are finding the number of steps they take until they meet each other, we can stop there. The solution is

$\boxed{\textbf{(A) }704}$

@@ Line 16: / Line 16: @@
 d = -12.5s + 10560
 d = 2.5s
@@ Line 26: / Line 27: @@
 s = 704
-Since we are finding the number of steps they take until they meet each other, we can stop there. The solution is <math>\boxed{\textbf{(A) }704)</math>
+Since we are finding the number of steps they take until they meet each other, we can stop there. The solution is
+<math>\boxed{\textbf{(A) }704}</math>
 ==See Also==

2018 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 16	Followed by Problem 18
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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