Difference between revisions of "2020 AMC 12A Problems/Problem 1"

Revision as of 12:25, 28 May 2020

Problem

Carlos took $70\%$ of a whole pie. Maria took one third of the remainder. What portion of the whole pie was left?

$\textbf{(A)}\ 10\%\qquad\textbf{(B)}\ 15\%\qquad\textbf{(C)}\ 20\%\qquad\textbf{(D)}\ 30\%\qquad\textbf{(E)}\ 35\%$

Solution 1

If Carlos took $70\%$ of the pie, $(100 - 70) = 30\%$ must be remaining. After Maria takes $\frac{1}{3}$ of the remaining $30\%,$ $1 - \frac{1}{3} = \frac{2}{3}$ is left.

Therefore:

$30\% \cdot \frac{2}{3} = \boxed{\textbf{C) }20\%}$

-Contributed by Awesome2.1, latex by quacker88

Video Solution

https://youtu.be/qJF3G7_IDgc

~IceMatrix

Direct BBCode link: [youtube]https://youtu.be/qJF3G7_IDgc[/youtube]

~cw357

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Difference between revisions of "2020 AMC 12A Problems/Problem 1"

Revision as of 12:25, 28 May 2020

Contents

Problem

Solution 1

Video Solution

See Also

@@ Line 20: / Line 20: @@
 ~IceMatrix
+Direct BBCode link:
+[youtube]https://youtu.be/qJF3G7_IDgc[/youtube]
+~cw357
 ==See Also==