Difference between revisions of "2010 AMC 12B Problems/Problem 1"
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− | == Problem | + | {{duplicate|[[2010 AMC 12B Problems|2010 AMC 12B #1]] and [[2010 AMC 10B Problems|2010 AMC 10B #2]]}} |
+ | |||
+ | == Problem == | ||
Makarla attended two meetings during her <math>9</math>-hour work day. The first meeting took <math>45</math> minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings? | Makarla attended two meetings during her <math>9</math>-hour work day. The first meeting took <math>45</math> minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings? | ||
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The total number of minutes in here <math>9</math>-hour work day is <math>9 \times 60 = 540.</math> | The total number of minutes in here <math>9</math>-hour work day is <math>9 \times 60 = 540.</math> | ||
The total amount of time spend in meetings in minutes is <math>45 + 45 \times 2 = 135.</math> | The total amount of time spend in meetings in minutes is <math>45 + 45 \times 2 = 135.</math> | ||
− | The answer is then <math>\frac{135}{540}</math> <math>= \boxed{25\%}</math> <math>\ | + | The answer is then <math>\frac{135}{540}</math> <math>= \boxed{25\%}</math> or <math>\boxed{(C)}</math> |
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/uAc9VHtRRPg?t=82 | ||
+ | |||
+ | ~IceMatrix | ||
== See also == | == See also == | ||
− | {{AMC12 box|year=2010| | + | {{AMC12 box|year=2010|before=First Question|num-a=2|ab=B}} |
+ | {{AMC10 box|year=2010|ab=B|num-b=1|num-a=3}} | ||
+ | {{MAA Notice}} |
Revision as of 00:49, 22 December 2020
- The following problem is from both the 2010 AMC 12B #1 and 2010 AMC 10B #2, so both problems redirect to this page.
Contents
Problem
Makarla attended two meetings during her -hour work day. The first meeting took minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings?
Solution
The total number of minutes in here -hour work day is The total amount of time spend in meetings in minutes is The answer is then or
Video Solution
https://youtu.be/uAc9VHtRRPg?t=82
~IceMatrix
See also
2010 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by First Question |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
2010 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.