Difference between revisions of "2021 AMC 10B Problems/Problem 5"
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+ | ==Problem== | ||
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The ages of Jonie's four cousins are distinct single-digit positive integers. Two of the cousins' ages multiplied together give <math>24</math>, while the other two multiply to <math>30</math>. What is the sum of the ages of Jonie's four cousins? | The ages of Jonie's four cousins are distinct single-digit positive integers. Two of the cousins' ages multiplied together give <math>24</math>, while the other two multiply to <math>30</math>. What is the sum of the ages of Jonie's four cousins? | ||
<math>\textbf{(A)} ~21 \qquad\textbf{(B)} ~22 \qquad\textbf{(C)} ~23 \qquad\textbf{(D)} ~24 \qquad\textbf{(E)} ~25</math> | <math>\textbf{(A)} ~21 \qquad\textbf{(B)} ~22 \qquad\textbf{(C)} ~23 \qquad\textbf{(D)} ~24 \qquad\textbf{(E)} ~25</math> | ||
− | ==Solution | + | ==Solution== |
First look at the two cousins' ages that multiply to <math>24</math>. Since the ages must be single-digit, the ages must either be <math>3 \text{ and } 8</math> or <math>4 \text{ and } 6.</math> | First look at the two cousins' ages that multiply to <math>24</math>. Since the ages must be single-digit, the ages must either be <math>3 \text{ and } 8</math> or <math>4 \text{ and } 6.</math> | ||
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We are required to find the sum of the ages, which is <cmath>3 + 8 + 5 + 6 = \boxed{(B) \text{ } 22}.</cmath> | We are required to find the sum of the ages, which is <cmath>3 + 8 + 5 + 6 = \boxed{(B) \text{ } 22}.</cmath> | ||
− | -PureSwag | + | -[[User:PureSwag|PureSwag]] |
+ | |||
+ | == Video Solution by OmegaLearn (Using Factors) == | ||
+ | https://youtu.be/oe7lnbDO8bo | ||
+ | |||
+ | ~ pi_is_3.14 | ||
+ | |||
+ | ==Video Solution by TheBeautyofMath== | ||
+ | https://youtu.be/gLahuINjRzU?t=857 | ||
+ | |||
+ | ~IceMatrix | ||
+ | |||
+ | ==Video Solution by Interstigation== | ||
+ | https://youtu.be/DvpN56Ob6Zw?t=358 | ||
+ | |||
+ | ~Interstigation | ||
== See Also == | == See Also == | ||
− | {{AMC10 box|year=2021|ab=B| | + | {{AMC10 box|year=2021|ab=B|num-b=4|num-a=6}} |
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 01:05, 23 February 2021
Contents
Problem
The ages of Jonie's four cousins are distinct single-digit positive integers. Two of the cousins' ages multiplied together give , while the other two multiply to . What is the sum of the ages of Jonie's four cousins?
Solution
First look at the two cousins' ages that multiply to . Since the ages must be single-digit, the ages must either be or
Next, look at the two cousins' ages that multiply to . Since the ages must be single-digit, the only ages that work are Remembering that all the ages must all be distinct, the only solution that works is when the ages are and .
We are required to find the sum of the ages, which is
Video Solution by OmegaLearn (Using Factors)
~ pi_is_3.14
Video Solution by TheBeautyofMath
https://youtu.be/gLahuINjRzU?t=857
~IceMatrix
Video Solution by Interstigation
https://youtu.be/DvpN56Ob6Zw?t=358
~Interstigation
See Also
2021 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.