Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "2018 AMC 8 Problems/Problem 17"

m (→‎Solution 1)
m (numerator was spelled wrong)
Line 6: Line 6:
 
==Solution 1==
 
==Solution 1==
  
−
Since Ella rides 5 times faster than Bella, the ratio of their speeds is 5:1. For Bella, we have D/R = t and for Ella, we have D/5r = t, however we know times for both girls must be the same, and so that means in D/5R = t, numertator becomes 5D(Ella travels 5 times the distance that Bella does). This means that Bella travels 1/6 of the way, and 1/6 of 10560 feet is 1760 feet. Bella also walks 2.5 feet in a step, and 1760 divided by 2.5 is <math>\boxed{\textbf{(A) }704}</math>.
+
Since Ella rides 5 times faster than Bella, the ratio of their speeds is 5:1. For Bella, we have D/R = t and for Ella, we have D/5r = t, however we know times for both girls must be the same, and so that means in D/5R = t, numerator becomes 5D(Ella travels 5 times the distance that Bella does). This means that Bella travels 1/6 of the way, and 1/6 of 10560 feet is 1760 feet. Bella also walks 2.5 feet in a step, and 1760 divided by 2.5 is <math>\boxed{\textbf{(A) }704}</math>.
  
 
==See Also==
 
==See Also==

Revision as of 20:08, 25 June 2021

Problem

Bella begins to walk from her house toward her friend Ella's house. At the same time, Ella begins to ride her bicycle toward Bella's house. They each maintain a constant speed, and Ella rides 5 times as fast as Bella walks. The distance between their houses is $2$ miles, which is $10,560$ feet, and Bella covers $2 \tfrac{1}{2}$ feet with each step. How many steps will Bella take by the time she meets Ella?

$\textbf{(A) }704\qquad\textbf{(B) }845\qquad\textbf{(C) }1056\qquad\textbf{(D) }1760\qquad \textbf{(E) }3520$

Solution 1

Since Ella rides 5 times faster than Bella, the ratio of their speeds is 5:1. For Bella, we have D/R = t and for Ella, we have D/5r = t, however we know times for both girls must be the same, and so that means in D/5R = t, numerator becomes 5D(Ella travels 5 times the distance that Bella does). This means that Bella travels 1/6 of the way, and 1/6 of 10560 feet is 1760 feet. Bella also walks 2.5 feet in a step, and 1760 divided by 2.5 is $\boxed{\textbf{(A) }704}$.

See Also

2018 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 16 		Followed by
Problem 18
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_8_Problems/Problem_17&oldid=156843"