Difference between revisions of "1970 AHSME Problems/Problem 29"
Audrey guo (talk | contribs) (→Solution) |
Audrey guo (talk | contribs) (→MaMaChiCk?!?!?!?!) |
||
(2 intermediate revisions by the same user not shown) | |||
Line 13: | Line 13: | ||
50 + (m-3)/12 = 30 + (m+6) | 50 + (m-3)/12 = 30 + (m+6) | ||
= 10hours + m = 10: 15 | = 10hours + m = 10: 15 | ||
− | |||
== See also == | == See also == |
Latest revision as of 23:32, 12 January 2022
Problem
It is now between 10:00 and 11:00 o'clock, and six minutes from now, the minute hand of a watch will be exactly opposite the place where the hour hand was three minutes ago. What is the exact time now?
Solution
50 + (m-3)/12 = 30 + (m+6) = 10hours + m = 10: 15
See also
1970 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 28 |
Followed by Problem 30 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.