Difference between revisions of "2022 AMC 8 Problems/Problem 5"

Revision as of 00:18, 9 January 2023

Problem

Anna and Bella are celebrating their birthdays together. Five years ago, when Bella turned $6$ years old, she received a newborn kitten as a birthday present. Today the sum of the ages of the two children and the kitten is $30$ years. How many years older than Bella is Anna?

$\textbf{(A) } 1 \qquad \textbf{(B) } 2 \qquad \textbf{(C) } 3 \qquad \textbf{(D) } 4 \qquad \textbf{(E) } ~5$

Solution

Video Solution

https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=323

~Interstigation

Video Solution

https://youtu.be/WY0m0jAj__Y

~savannahsolver

Video Solution

https://youtu.be/Q0R6dnIO95Y?t=212

~STEMbreezy

2022 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

@@ Line 7: / Line 7: @@
 ==Solution==
-Five years ago, Bella was <math>6</math> years old, and the kitten was <math>0</math> years old.
-Today, Bella is <math>11</math> years old, and the kitten is <math>5</math> years old. It follows that Anna is <math>30-11-5=14</math> years old.
-Therefore, Anna is <math>14-11=\boxed{\textbf{(C) } 3}</math> years older than Bella.
-~MRENTHUSIASM
 ==Video Solution==
 https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=323

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Difference between revisions of "2022 AMC 8 Problems/Problem 5"

Revision as of 00:18, 9 January 2023

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Problem

Solution

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Video Solution

Video Solution

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