Difference between revisions of "2022 AMC 8 Problems/Problem 2"
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==Solution== | ==Solution== | ||
− | We | + | We can substitute <math>5</math>, <math>3</math>, and <math>6</math> into the function definitions: |
<cmath>\begin{align*} | <cmath>\begin{align*} | ||
(5 \, \blacklozenge \, 3) \, \bigstar \, 6 &= \left(5^2-3^2\right) \, \bigstar \, 6 \\ | (5 \, \blacklozenge \, 3) \, \bigstar \, 6 &= \left(5^2-3^2\right) \, \bigstar \, 6 \\ | ||
+ | (5 \, \blacklozenge \, 3) \, \bigstar \, 6 &= \left(25-9\right) \, \bigstar \, 6 \\ | ||
&= 16 \, \bigstar \, 6 \\ | &= 16 \, \bigstar \, 6 \\ | ||
&= (16-6)^2 \\ | &= (16-6)^2 \\ | ||
&= \boxed{\textbf{(D) } 100}. | &= \boxed{\textbf{(D) } 100}. | ||
\end{align*}</cmath> | \end{align*}</cmath> | ||
− | <i>~pog</i> | + | <i>~pog</i> ~MathFun1000 (Minor Edits) |
==Video Solution== | ==Video Solution== |
Revision as of 22:06, 16 January 2023
Problem
Consider these two operations: What is the output of
Solution
We can substitute , , and into the function definitions: ~pog ~MathFun1000 (Minor Edits)
Video Solution
https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=91 ~Interstigation
Video Solution 2
~savannahsolver
Video Solution
https://youtu.be/Q0R6dnIO95Y?t=53
~STEMbreezy
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.