Difference between revisions of "2022 AMC 8 Problems/Problem 5"
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==Solution== | ==Solution== | ||
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Five years ago, Bella was <math>6</math> years old, and the kitten was <math>0</math> years old. | Five years ago, Bella was <math>6</math> years old, and the kitten was <math>0</math> years old. | ||
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~MRENTHUSIASM | ~MRENTHUSIASM | ||
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+ | ==Video Solution by Math-X (First understand the problem!!!)== | ||
+ | https://youtu.be/oUEa7AjMF2A?si=AeqPj9sQgiBU3_lL&t=585 | ||
+ | |||
+ | ~Math-X | ||
+ | |||
+ | ==Video Solution (CREATIVE THINKING!!!)== | ||
+ | https://youtu.be/NuRFgRUpV7o | ||
+ | |||
+ | ~Education, the Study of Everything | ||
+ | |||
==Video Solution== | ==Video Solution== | ||
https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=323 | https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=323 | ||
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~STEMbreezy | ~STEMbreezy | ||
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+ | ==Video Solution== | ||
+ | https://youtu.be/Cb5as-fLejk | ||
+ | |||
+ | ~harungurcan | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2022|num-b=4|num-a=6}} | {{AMC8 box|year=2022|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 21:30, 11 January 2024
Contents
Problem
Anna and Bella are celebrating their birthdays together. Five years ago, when Bella turned years old, she received a newborn kitten as a birthday present. Today the sum of the ages of the two children and the kitten is years. How many years older than Bella is Anna?
Solution
Five years ago, Bella was years old, and the kitten was years old.
Today, Bella is years old, and the kitten is years old. It follows that Anna is years old.
Therefore, Anna is years older than Bella.
~MRENTHUSIASM
Video Solution by Math-X (First understand the problem!!!)
https://youtu.be/oUEa7AjMF2A?si=AeqPj9sQgiBU3_lL&t=585
~Math-X
Video Solution (CREATIVE THINKING!!!)
~Education, the Study of Everything
Video Solution
https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=323
~Interstigation
Video Solution
~savannahsolver
Video Solution
https://youtu.be/Q0R6dnIO95Y?t=212
~STEMbreezy
Video Solution
~harungurcan
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.