Difference between revisions of "2011 AMC 8 Problems/Problem 1"
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Margie bought <math> 3 </math> apples at a cost of <math> 50 </math> cents per apple. She paid with a 5-dollar bill. How much change did Margie receive? | Margie bought <math> 3 </math> apples at a cost of <math> 50 </math> cents per apple. She paid with a 5-dollar bill. How much change did Margie receive? | ||
− | <math>\textbf{(A)}\ \textdollar 1.50 \qquad \textbf{(B)}\ \textdollar 2.00 \qquad \textbf{(C)}\ \textdollar 2.50 \qquad \textbf{(D)}\ \textdollar 3.00 \qquad \textbf{( | + | <math>\textbf{(A)}\ \textdollar 1.50 \qquad \textbf{(B)}\ \textdollar 2.00 \qquad \textbf{(C)}\ \textdollar 2.50 \qquad \textbf{(D)}\ \textdollar 3.00 \qquad \textbf{(E)}\ \textdollar 3.50</math> |
==Solution== | ==Solution== | ||
− | <math>50</math> cents is equivalent to <math>\textdollar 0.50.</math> Then the three apples cost <math>3 \times \textdollar 0.50 = \textdollar 1.50.</math> The change Margie receives is <math>\textdollar 5.00 - \textdollar 1.50 = \boxed{\textbf{( | + | <math>50</math> cents is equivalent to <math>\textdollar 0.50.</math> Then the three apples cost <math>3 \times \textdollar 0.50 = \textdollar 1.50.</math> The change Margie receives is <math>\textdollar 5.00 - \textdollar 1.50 = \boxed{\textbf{(E)}\ \textdollar 3.50}</math> |
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+ | -Mathloveraldoxxx5223 | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|before=First Problem|num-a=2}} | {{AMC8 box|year=2011|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 12:26, 13 January 2024
Problem
Margie bought apples at a cost of cents per apple. She paid with a 5-dollar bill. How much change did Margie receive?
Solution
cents is equivalent to Then the three apples cost The change Margie receives is
-Mathloveraldoxxx5223
See Also
2011 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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