Difference between revisions of "2004 AMC 12B Problems/Problem 1"
m (2004 AMC 12B/Problem 1 moved to 2004 AMC 12B Problems/Problem 1: fmt) |
m (solution) |
||
Line 1: | Line 1: | ||
==Problem== | ==Problem== | ||
− | + | At each basketball practice last week, Jenny made twice as many free throws as she made at the previous practice. At her fifth practice she made <math>48</math> free throws. How many free throws did she make at the first practice? | |
− | <math>\mathrm {(A)} | + | <math>\mathrm {(A)} 3 \qquad \mathrm {(B)} 6\qquad \mathrm {(C)} 9 \qquad \mathrm {(D)} 12 \qquad \mathrm {(E)} 15</math> |
==Solution== | ==Solution== | ||
− | + | Each day Jenny makes half as many free throws as she does at the next practice. Hence on the fourth day she made <math>\frac{1}{2} \cdot 48 = 24</math> free throws, on the third <math>12</math>, on the second <math>6</math>, and on the first <math>3 \Rightarrow \mathrm{(A)}</math>. | |
− | |||
− | |||
− | <math> | ||
==See Also== | ==See Also== | ||
{{AMC12 box|year=2004|ab=B|before=First Question|num-a=2}} | {{AMC12 box|year=2004|ab=B|before=First Question|num-a=2}} | ||
+ | |||
+ | [[Category:Introductory Algebra Problems]] |
Revision as of 18:03, 10 February 2008
Problem
At each basketball practice last week, Jenny made twice as many free throws as she made at the previous practice. At her fifth practice she made free throws. How many free throws did she make at the first practice?
Solution
Each day Jenny makes half as many free throws as she does at the next practice. Hence on the fourth day she made free throws, on the third , on the second , and on the first .
See Also
2004 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by First Question |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |