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Difference between revisions of "2022 AMC 8 Problems/Problem 22"

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<math>\textbf{(A) } 17 \qquad \textbf{(B) } 19 \qquad \textbf{(C) } 20 \qquad \textbf{(D) } 21 \qquad \textbf{(E) } 23</math>
 
<math>\textbf{(A) } 17 \qquad \textbf{(B) } 19 \qquad \textbf{(C) } 20 \qquad \textbf{(D) } 21 \qquad \textbf{(E) } 23</math>
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== Video Solution by Pi Academy (Fast and Easy) ==
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https://youtu.be/97Ll2ylPFFc?si=s-yb3FdhSdeLyYR7
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~ Pi Academy
  
 
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==Solution 1==
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~kn07
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==Video Solution by Math-X (First understand the problem!!!)==
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https://youtu.be/oUEa7AjMF2A?si=qG63Tc0Nj4iuSeSr&t=4163
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~Math-X
  
 
==Video Solution(🚀70 seconds🚀)==
 
==Video Solution(🚀70 seconds🚀)==
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Please like and subscribe!
 
Please like and subscribe!
  
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==See Also==  
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== Video Solution by Pi Academy ==
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https://youtu.be/97Ll2ylPFFc?feature=shared
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~ Pi Academy
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==See Also==
 
{{AMC8 box|year=2022|num-b=21|num-a=23}}
 
{{AMC8 box|year=2022|num-b=21|num-a=23}}
 
{{MAA Notice}}
 
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Latest revision as of 12:02, 8 December 2024

Problem

A bus takes $2$ minutes to drive from one stop to the next, and waits $1$ minute at each stop to let passengers board. Zia takes $5$ minutes to walk from one bus stop to the next. As Zia reaches a bus stop, if the bus is at the previous stop or has already left the previous stop, then she will wait for the bus. Otherwise she will start walking toward the next stop. Suppose the bus and Zia start at the same time toward the library, with the bus $3$ stops behind. After how many minutes will Zia board the bus?

2022 AMC 8 Problem 22 Diagram.png

$\textbf{(A) } 17 \qquad \textbf{(B) } 19 \qquad \textbf{(C) } 20 \qquad \textbf{(D) } 21 \qquad \textbf{(E) } 23$

Video Solution by Pi Academy (Fast and Easy)

https://youtu.be/97Ll2ylPFFc?si=s-yb3FdhSdeLyYR7

~ Pi Academy

Solution 1

Initially, suppose that the bus is at Stop $0$ (starting point) and Zia is at Stop $3.$

We construct the following table of $5$-minute intervals: \[\begin{array}{c||c|c} & & \\ [-2.5ex] \textbf{Time} & \textbf{Bus's Location} & \textbf{Zia's Location} \\ [0.5ex] \hline & & \\ [-2ex] \boldsymbol{5} \ \textbf{Minutes} & \text{Stop} \ 2 \ \text{(Waiting)} & \text{Stop} \ 4 \\ \boldsymbol{10} \ \textbf{Minutes} & \text{Midpoint of Stops} \ 3 \ \text{and} \ 4 & \text{Stop} \ 5 \\ \boldsymbol{15} \ \textbf{Minutes} & \text{Stop} \ 5 \ \text{(Leaving)} & \text{Stop} \ 6 \end{array}\] Note that Zia will wait for the bus after $15$ minutes, and the bus will arrive $2$ minutes later.

Therefore, the answer is $15+2=\boxed{\textbf{(A) } 17}.$

~MRENTHUSIASM

Solution 2

Since Zia will wait for the bus if the bus is at the previous stop, we can create an equation to solve for when the bus is at the previous stop. The bus travels $\frac{1}{3}$ of a stop per minute, and Zia travels $\frac{1}{5}$ of a stop per minute. Now we create the equation, $\frac{1}{3}m = \frac{1}{5}m + 3 - 1$ (the $-1$ accounts for us wanting to find when the bus reaches the stop before Zia's). Solving, we find that $m=15.$ Now Zia has to wait $2$ minutes for the bus to reach her, so our answer is $15+2=\boxed{\textbf{(A) } 17}.$

~kn07

Video Solution by Math-X (First understand the problem!!!)

https://youtu.be/oUEa7AjMF2A?si=qG63Tc0Nj4iuSeSr&t=4163

~Math-X

Video Solution(🚀70 seconds🚀)

https://youtu.be/3xtTYyciReI

~Education, the Study of Everything

Video Solution by OmegaLearn

https://youtu.be/XixU0JZ5FLk?t=704

~ pi_is_3.14

Video Solution

https://www.youtube.com/watch?v=SFp4HaieEBg

~Mathematical Dexterity

Video Solution

https://youtu.be/Ij9pAy6tQSg?t=2111

~Interstigation

Video Solution

https://www.youtube.com/watch?v=m2D9W9LWUpU

~David

Video Solution

https://youtu.be/0orAAUaLIO0?t=137

~STEMbreezy

Video Solution

https://youtu.be/KYnheOL86oA

~savannahsolver

Video Solution

https://youtu.be/K_V7ACKBhhs

Please like and subscribe!

Video Solution by Pi Academy

https://youtu.be/97Ll2ylPFFc?feature=shared

~ Pi Academy

See Also

2022 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 21 		Followed by
Problem 23
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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