Difference between revisions of "1989 AJHSME Problems/Problem 12"
5849206328x (talk | contribs) (New page: ==Problem== <math>\frac{1-\frac{1}{3}}{1-\frac{1}{2}} =</math> <math>\text{(A)}\ \frac{1}{3} \qquad \text{(B)}\ \frac{2}{3} \qquad \text{(C)}\ \frac{3}{4} \qquad \text{(D)}\ \frac{3}{2} ...) |
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